将网络摄像头/相机视频流上传到服务器的 HTML5 解决方案 [英] HTML5 solution to upload a webcam/camera video stream to server

问题描述

使用 getUserMedia 我可以从客户端的网络摄像头/相机捕获视频流.并使用 video 标签我可以在客户端的浏览器上显示它.代码:

<视频自动播放><script type="text/javascript">window.URL = window.URL ||window.webkitURL;navigator.getUserMedia = navigator.getUserMedia ||navigator.webkitGetUserMedia ||navigator.mozGetUserMedia ||navigator.msGetUserMedia;var video = $('video')[0];var 失败 = 函数(e){console.log('拒绝！', e);};如果(导航器.getUserMedia){navigator.getUserMedia( {video: true, audio: true}, function( stream ) {video.src = window.URL.createObjectURL(stream);}， 失败的)} 别的 {console.log('不支持！');}

现在是否可以将此视频流作为实时供稿或在用户完成录制并决定上传后发送到服务器?

我发现了几个例子:

• 通过 websocket 向服务器发送二进制图像
• 定期捕获流视频的帧并将其作为图像发送

解决方案

MediaStreamRecorder 是一个用于记录 getUserMedia() 流的 WebRTC API.它允许网络应用从实时音频/视频会话创建文件.

 <视频自动播放><script language="javascript" type="text/javascript">功能 onVideoFail(e) {console.log('网络摄像头失败！', e);};函数 hasGetUserMedia() {//注意:Opera 是无前缀的.return !!(navigator.getUserMedia || navigator.webkitGetUserMedia ||navigator.mozGetUserMedia ||navigator.msGetUserMedia);}如果(hasGetUserMedia()){//好！} 别的 {alert('您的浏览器不支持getUserMedia()');}window.URL = window.URL ||window.webkitURL;navigator.getUserMedia = navigator.getUserMedia ||navigator.webkitGetUserMedia ||navigator.mozGetUserMedia ||navigator.msGetUserMedia;var video = document.querySelector('video');var 流记录器；var 网络摄像头流；如果(navigator.getUserMedia){navigator.getUserMedia({audio: true, video: true}, function(stream) {video.src = window.URL.createObjectURL(stream);网络摄像头流 = 流；//streamrecorder = webcamstream.record();}, onVideoFail);} 别的 {警报('失败')；}功能开始录音(){streamRecorder = webcamstream.record();设置超时(停止录音，10000)；}功能停止录音(){streamRecorder.getRecordedData(postVideoToServer);}功能 postVideoToServer(videoblob) {无功数据 = {};data.video = videoblob;data.metadata = '测试元数据';data.action = "upload_video";jQuery.post("http://www.kongraju.in/uploadvideo.php", data, onUploadSuccess);}函数 onUploadSuccess() {警报('视频上传')；}<div id="网络摄像头控件"><button class="recordbutton" onclick="startRecording();">RECORD</button>

规格:

http://www.w3.org/TR/mediastream-recording/

您可以将录制的文件发送到服务器.

Using getUserMedia I can capture video stream from client's webcam/camera. And using video tag I can show it on client's browser. Code:

<video autoplay></video>

<script type="text/javascript">
    window.URL = window.URL || window.webkitURL;
    navigator.getUserMedia  = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia || navigator.msGetUserMedia;

    var video = $('video')[0];

    var failed = function(e) {
        console.log('Denied!', e);
    };

    if( navigator.getUserMedia ) {
        navigator.getUserMedia( {video: true, audio: true}, function( stream ) {
                video.src = window.URL.createObjectURL(stream);
            }, failed
        )
    } else {
        console.log( 'Not supported!' );
    }
</script>

Now is it possible to send this video stream, either as a realtime feed or after user has done recording and decided to upload, to a server?

I found few examples of:

• sending binary images to server over websocket
• Periodically capture frame of streaming video and send that as image

解决方案

MediaStreamRecorder is a WebRTC API for recording getUserMedia() streams . It allows web apps to create a file from a live audio/video session.

 <video autoplay></video>

    <script language="javascript" type="text/javascript">
    function onVideoFail(e) {
        console.log('webcam fail!', e);
      };

    function hasGetUserMedia() {
      // Note: Opera is unprefixed.
      return !!(navigator.getUserMedia || navigator.webkitGetUserMedia ||
                navigator.mozGetUserMedia || navigator.msGetUserMedia);
    }

    if (hasGetUserMedia()) {
      // Good to go!
    } else {
      alert('getUserMedia() is not supported in your browser');
    }

    window.URL = window.URL || window.webkitURL;
    navigator.getUserMedia  = navigator.getUserMedia || 
                             navigator.webkitGetUserMedia ||
                              navigator.mozGetUserMedia || 
                               navigator.msGetUserMedia;

    var video = document.querySelector('video');
    var streamRecorder;
    var webcamstream;

    if (navigator.getUserMedia) {
      navigator.getUserMedia({audio: true, video: true}, function(stream) {
        video.src = window.URL.createObjectURL(stream);
        webcamstream = stream;
    //  streamrecorder = webcamstream.record();
      }, onVideoFail);
    } else {
        alert ('failed');
    }

    function startRecording() {
        streamRecorder = webcamstream.record();
        setTimeout(stopRecording, 10000);
    }
    function stopRecording() {
        streamRecorder.getRecordedData(postVideoToServer);
    }
    function postVideoToServer(videoblob) {

        var data = {};
        data.video = videoblob;
        data.metadata = 'test metadata';
        data.action = "upload_video";
        jQuery.post("http://www.kongraju.in/uploadvideo.php", data, onUploadSuccess);
    }
    function onUploadSuccess() {
        alert ('video uploaded');
    }

    </script>

    <div id="webcamcontrols">
        <button class="recordbutton" onclick="startRecording();">RECORD</button>
    </div>

Spec:

http://www.w3.org/TR/mediastream-recording/

you can send recorded file to server.

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