Laravel 表单模型绑定 [英] Laravel form model binding
问题描述
我一直在阅读有关此功能的信息:.真的很有帮助.
如果您的表单只有来自单个模型的字段，则您的更新方法可能非常简单，如下所示:
公共函数更新($id){$user = User::find($id);if (!$user->update(Input::all())) {返回重定向::返回()->with('message', '保存模型时出错')->withInput();}return Redirect::route('user.saved')->with('message', '用户更新.');}对于稍微复杂一点的表单，编码人员将不得不向他们的控制器添加更多逻辑，如果您进行更多研究，我认为您可以做到这一点:
公共函数更新($id){$user = User::find($id);$inputs = Input::all();如果 (!$user->update($inputs)) {$address = new UserAddress($inputs['address']);$user->address()->save($address);...}...}I've been reading about this feature: http://laravel.com/docs/html#form-model-binding
And it looks really neat, but there are couple of things that I'm not certain about.
Do I need to put any code in the controller action to process this form? What does that look like?
The model (User) I want to bind in my form has a separate table for addresses. So I want to be able to fill out the User model's fields, but also the fields for the related Address model. Can I do that with form-model-binding, or do I have to handle the form manually?
Or, failing that, can I use form model binding for the user fields, but manually handle the address fields?
You don't need any different code in your controller to process this form. All your (named) form variables will be in Input::all().
The model ($user) you pass in
Form::model($user, array('route' => array('user.update', $user->id)))
Is just any record you need to, if you have more than one table involved, you'll have to do something like
$user = User::where('id',$userID)
->leftJoin('users_addresses', 'users_addresses.user_id', '=', 'users.id')
->first();
And pass this composed model to your Form::model().
How you name your inputs is entirely up to you, because you'll have to write the logic to process your form. But, in my opinion users_address[street] for the address inputs is good, because you'll end up with an array of addresses columns that you can pass right away to your UserAddress model.
<html>
<head>
<title></title>
</head>
<body>
{{ Form::model($user, array('route' => array('user.update', $user->id))) }}
{{ Form::label('first_name', 'First Name:', array('class' => 'address')) }}
{{ Form::text('first_name') }}
{{ Form::label('last_name', 'Last Name:', array('class' => 'address')) }}
{{ Form::text('last_name') }}
{{ Form::label('email', 'E-Mail Address', array('class' => 'address')) }}
{{ Form::text('email') }}
{{ Form::label('address[street1]', 'Address (Street 1)', array('class' => 'address')) }}
{{ Form::text('address[street1]') }}
{{ Form::label('address[street2]', 'Address (Street 2)', array('class' => 'address')) }}
{{ Form::text('address[street2]') }}
{{ Form::label('ddress[city]', 'City', array('class' => 'address')) }}
{{ Form::text('address[city]') }}
{{ Form::label('address[state]', 'State', array('class' => 'address')) }}
{{ Form::text('address[state]') }}
{{ Form::label('address[zip]', 'Zip Code', array('class' => 'address')) }}
{{ Form::text('address[zip]') }}
{{ Form::submit('Send this form!') }}
{{ Form::close() }}
</body>
</html>
And if you do dd( Input::all() ) in your controller, you'll get something like this:
This result is provided by Kint's dd(): https://github.com/raveren/kint. Really helpful.
If your form just have fields from a single Model, your update method can be very simple and look something like:
public function update($id)
{
$user = User::find($id);
if (!$user->update(Input::all())) {
return Redirect::back()
->with('message', 'Something wrong happened while saving your model')
->withInput();
}
return Redirect::route('user.saved')
->with('message', 'User updated.');
}
On forms a little bit more complex, coders will have to add more logic to their controllers, in you case with a little bit more of research I think you can make this happen:
public function update($id)
{
$user = User::find($id);
$inputs = Input::all();
if (!$user->update($inputs)) {
$address = new UserAddress($inputs['address']);
$user->address()->save($address);
...
}
...
}
这篇关于Laravel 表单模型绑定的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
