Laravel Eloquent - 在哪里 [英] Laravel Eloquent - Where In All

问题描述

在 Laravel 4.2 中，我试图实现一个返回所有用户的查询，这些用户具有所有特定活动.截至目前，我有一个查询返回所有具有许多活动之一的用户:

In Laravel 4.2, I am trying to achieve a query that returns all users, that have all of certain activities. As of now, I have a query that returns all users that have one of many activities:

//$selectedActivities being an array
        $userByActivities = User::with('activities')
                ->whereHas('activities', function($query) use($selectedActivities){
                    $query->whereIn('id', $selectedActivities);
                })->get();

更清楚:给定活动a,b,c.我正在寻找具有活动 a AND b AND c 的所有用户.我的查询返回具有活动 a OR b OR c 的所有用户.

To be more clear: given activities a,b,c. I am looking for all users that have activity a AND b AND c. My query returns all users that have activity a OR b OR c.

感谢您的帮助.

lukasgeiter 提供的解决方案导致以下查询:

The solution offered by lukasgeiter results in following query:

select * from `users` where 
        (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '7') >= 1 
        and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '3') >= 1 
        and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '1') >= 1 
        and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '2') >= 1

而 Jarek Tkaczyk 提供的解决方案:

Whereas the solution offered by Jarek Tkaczyk:

$userByActivities = User::with('activities')
 ->whereHas('activities', function($query) use($selectedActivities) {
     $query->selectRaw('count(distinct id)')->whereIn('id', $selectedActivities);
 }, '=', count($selectedActivities))->get();

对于类似的请求，会产生以下查询:

for a similar request, results in following query:

select * from `users` where (select count(distinct id) from `activities` 
    inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` 
    where `activity_user`.`user_id` = `users`.`id` and `id` in ('7', '3', '1', '2')) = 4

推荐答案

您必须为此添加多个 whereHas:

You'll have to add multiple whereHas for that:

$query = User::with('activities');
foreach($selectedActivities as $activityId){
    $query->whereHas('activities', function($q) use ($activityId){
        $q->where('id', $activityId);
    });
}
$userByActivities = $query->get();

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