Python 中的错误继续下一步 [英] On Error Resume Next in Python

问题描述

do_magic() # Throws exception, doesn't execute do_foo and do_bar
do_foo()
do_bar()

片段 2

try:
    do_magic() # Doesn't throw exception, doesn't execute do_foo and do_bar
    do_foo() 
    do_bar()
except:
    pass

代码段 3

try: do_magic(); except: pass
try: do_foo()  ; except: pass
try: do_bar()  ; except: pass

有没有办法优雅地编写代码片段 3?

Is there a way to write code snippet 3 elegantly?

• 如果 do_magic() 失败与否，do_foo() 和 do_bar() 应该被执行.
• 如果 do_foo() 失败与否，do_bar() 应该被执行.

• if do_magic() fails or not, do_foo() and do_bar() should be executed.
• if do_foo() fails or not, do_bar() should be executed.

在 Basic/Visual Basic/VBS 中，有一个名为 On Error Resume Next 的语句可以执行此操作.

In Basic/Visual Basic/VBS, there's a statement called On Error Resume Next which does this.

推荐答案

在 Python 3.4 以后，您可以使用 contextlib.suppress:

In Python 3.4 onwards, you can use contextlib.suppress:

from contextlib import suppress

with suppress(Exception): # or, better, a more specific error (or errors)
    do_magic()
with suppress(Exception):
    do_foo()
with suppress(Exception):
    do_bar()

或者，fuckit.

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