方法中带有超类参数的Java getMethod [英] Java getMethod with superclass parameters in method
问题描述
给定:
class A
{
public void m(List l) { ... }
}
假设我想通过反射调用方法 m
,将 ArrayList 作为参数传递给 m
:
Let's say I want to invoke method m
with reflection, passing an ArrayList as the parameter to m
:
List myList = new ArrayList();
A a = new A();
Method method = A.class.getMethod("m", new Class[] { myList.getClass() });
method.invoke(a, Object[] { myList });
第 3 行的 getMethod
将抛出 NoSuchMethodException
,因为 myList 的运行时类型是 ArrayList,而不是 List.
The getMethod
on line 3 will throw NoSuchMethodException
because the runtime type of myList is ArrayList, not List.
是否有一种不需要了解 A 类参数类型知识的通用方法?
Is there a good generic way around this that doesn't require knowledge of class A's parameter types?
推荐答案
如果你知道类型是 List
,那么使用 List.class
作为参数.
If you know the type is List
, then use List.class
as argument.
如果您事先不知道类型,请想象您有:
If you don't know the type in advance, imagine you have:
public void m(List l) {
// all lists
}
public void m(ArrayList l) {
// only array lists
}
如果有自动方法,反射应该调用哪个方法?
Which method should the reflection invoke, if there is any automatic way?
如果需要,您可以使用 Class.getInterfaces()
或 Class.getSuperclass()
但这要视情况而定.
If you want, you can use Class.getInterfaces()
or Class.getSuperclass()
but this is case-specific.
您可以在这里做的是:
public void invoke(Object targetObject, Object[] parameters,
String methodName) {
for (Method method : targetObject.getClass().getMethods()) {
if (!method.getName().equals(methodName)) {
continue;
}
Class<?>[] parameterTypes = method.getParameterTypes();
boolean matches = true;
for (int i = 0; i < parameterTypes.length; i++) {
if (!parameterTypes[i].isAssignableFrom(parameters[i]
.getClass())) {
matches = false;
break;
}
}
if (matches) {
// obtain a Class[] based on the passed arguments as Object[]
method.invoke(targetObject, parametersClasses);
}
}
}
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