Python - 如何在 int 转换输入中的空值后中断 while 循环? [英] Python - How to break while loop after empty value in a int turning input?

问题描述

我想在输入空输入时使 while 循环中断.我知道错误是由于 int 函数造成的，因为它无法将空输入转换为整数，但我该如何做我想要写的?

I want to make the while loop break when empty input is typed. I know that the error is due to the int function because it cant turn to integer an empty input but how can i do what i'm trying to write?

while True:
    numb = int(input("number"))
    if numb % 2 == 0:
        print("this number is even")
    elif numb % 2 != 0:
        print("this number is odd")
    elif numb == '':
        break

推荐答案

这行得通:

while True:
    try:
        numb = int(input("number"))
    except ValueError:
        break
    if numb % 2 == 0:
        print("this number is even")
    elif numb % 2 != 0:
        print("this number is odd")

如果输入无法转换为整数，则只处理异常.现在，任何不是整数的输入都会终止循环.

Just handle the exception if the input cannot be converted into an integer. Now, any input that is not an integer would terminate the loop.

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