如果测试哈希有任何一个数字键的 [英] Testing if a hash has any of a number of keys

问题描述

我想知道是否有更好的方法来测试散列是否具有数组中的任何键.我想像这样使用它:

I was wondering if there was a better way to test if a hash has any keys from an array. I want to use it something like this:

keys = %w[k1 k2 k5 k6]
none = true if hash.key?(keys)

或者我必须循环这个?

推荐答案

无需循环:

(hash.keys & keys).any? # => true

说明:

.keys 将散列中的所有键作为数组返回.& 与两个数组相交，返回两个数组中存在的任何对象.最后，.any? 检查数组相交是否有任何值.

.keys returns all keys in a hash as an array. & intersects two arrays, returning any objects that exists in both arrays. Finally, .any? checks if the array intersect has any values.

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