从主要包含空值的 Comparables 列表中获取最小值和最大值的最佳方法是什么? [英] What is the best way to get min and max value from a list of Comparables that main contain null values?

问题描述

我正在考虑这样的事情:

I am thinking about something like this:

public static <T extends Comparable<T>> T minOf(T...ts){        
    SortedSet<T> set = new TreeSet<T>(Arrays.asList(ts));
    return set.first();
}

public static <T extends Comparable<T>> T maxOf(T...ts){
    SortedSet<T> set = new TreeSet<T>(Arrays.asList(ts));
    return set.last();
}

但不是空安全的，这也是我想要的.

But is not null safe, which is something I want too.

你知道解决这个问题的更好方法吗?

Do you know a better way to solve this problem?

评论后我也试过 min():

After the comments I have also tried min():

public static <T extends Comparable<T>> T minOf(T...ts){        
    return Collections.min(Arrays.asList(ts), new Comparator<T>(){

        public int compare(T o1, T o2) {
            if(o1!=null && o2!=null){
                return o1.compareTo(o2);
            }else if(o1!=null){
                return 1;
            }else{
                return -1;  
            }
        }});
}

你怎么看?

推荐答案

Collections.max?

你为什么关心空安全?您确定要在您的集合中允许空值吗?

And why do you care about null safety? Are you sure you want to allow nulls to be in your Collection?

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