如何从小部件扩展导航到 UIKit viewController? [英] How to navigate from widget extension to UIKit viewController?

问题描述

我目前正在尝试使用 SwiftUI 制作一个小部件.假设我的代码是这样的:

I am currently trying to make a widget with SwiftUI. Let's say my code is like this:

struct WidgetView: View {
    var data : DataProvider.Entry
    var body: some View {
        ZStack {
            Image("Clicker")
                .padding(.all, 15)
        }.widgetURL(URL(string: "ClickerViewController"))
        .padding(.all, 30)
        .background(Color.green)
    }
}

目前，点击小部件会打开应用程序的主屏幕.想要导航到特定屏幕.支持的家庭:.systemSmall - 所以需要使用 .widgetURL 而不是 .Link

At the moment, tapping the widget opens the home screen of the app. Want to navigate to a specific screen. supportedFamilies: .systemSmall - so need to use .widgetURL and not .Link

那么 URL 是 Clicker 的地方，如何导航到名为 ClickerViewController 的 viewController?如何处理这些链接?在不久的将来，任何示例或解释都会对我和许多其他人有所帮助；)

So where the URL is Clicker, how to navigate to viewController that is called ClickerViewController? How to handle these links? Any examples or explaining would help me and a lot of others in the near future I guess ;)

谢谢！

推荐答案

这里有可能的方法

var body: some Scene {
    @StateObject private var appState = AppState()

    WindowGroup {
        ContentView()
            .environmentObject(appState)
            .onOpenURL(perform: { url in
                appState.handle(url)       // redirect to app state
            })
    }
}

和 AppState 可以有，例如<​​/p>

and AppState can have, for example

class AppState: ObservableObject {
    @Published var appScreen: _SomeEnumType_

    func handle(url: URL) {
        // ... update `appScreen` here correnspondingly
    }
}

因此在 ContentView 内，您可以根据应用状态切换显示的视图.

so inside ContentView depending on app state you can switch shown views.

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