如何在grep中进行非贪婪匹配? [英] How to do a non-greedy match in grep?

问题描述

我想 grep 最短的匹配，模式应该是这样的:

I want to grep the shortest match and the pattern should be something like:

<car ... model=BMW ...>
...
...
...
</car>

... 表示任意字符，输入为多行.

... means any character and the input is multiple lines.

推荐答案

您正在寻找非贪婪(或惰性)匹配.要在正则表达式中获得非贪婪匹配，您需要在量词后使用修饰符 ?.例如，您可以将 .* 更改为 .*?.

You're looking for a non-greedy (or lazy) match. To get a non-greedy match in regular expressions you need to use the modifier ? after the quantifier. For example you can change .* to .*?.

默认情况下 grep 不支持非贪婪修饰符，但您可以使用 grep -P 来使用 Perl 语法.

By default grep doesn't support non-greedy modifiers, but you can use grep -P to use the Perl syntax.

这篇关于如何在grep中进行非贪婪匹配?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！