您可以在字符串拆分中使用零宽度匹配正则表达式吗? [英] Can you use zero-width matching regex in String split?

问题描述

System.out.println(
    Arrays.deepToString(
        "abc<def>ghi".split("(?:<)|(?:>)")
    )
);

这会打印 [abc, def, ghi]，就像我在 "<|>" 上拆分一样.我希望它打印 [abc, <def>, ghi].有没有办法使用一些正则表达式魔法来完成我在这里想要的?

This prints [abc, def, ghi], as if I had split on "<|>". I want it to print [abc, <def>, ghi]. Is there a way to work some regex magic to accomplish what I want here?

也许是一个更简单的例子:

Perhaps a simpler example:

System.out.println(
    Arrays.deepToString(
        "Hello! Oh my!! Good bye!!".split("(?:!+)")
    )
);

这会打印[Hello, Oh my, Good bye].我想让它打印 [Hello!, Oh my!!, Good bye!!].`.

This prints [Hello, Oh my, Good bye]. I want it to print [Hello!, Oh my!!, Good bye!!]. `.

推荐答案

感谢来自 Cine 的信息，我认为这些就是我正在寻找的答案:

Thanks to information from Cine, I think these are the answers I'm looking for:

System.out.println(
    Arrays.deepToString(
        "abc<def>ghi<x><x>".split("(?=<)|(?<=>)")
    )
); // [abc, <def>, ghi, <x>, <x>]


System.out.println(
    Arrays.deepToString(
        "Hello! Oh my!! Good bye!! IT WORKS!!!".split("(?<=!++)")
    )
); // [Hello!,  Oh my!!,  Good bye!!,  IT WORKS!!!]

现在，通过对所有不同的量词进行试验，诚实地发现了第二个量词.既不是贪婪也不是勉强工作，而是占有欲.

Now, the second one was honestly discovered by experimenting with all the different quantifiers. Neither greedy nor reluctant work, but possessive does.

我仍然不知道为什么.

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