如何将逗号分隔的字符串解析为列表(警告)? [英] How can i parse a comma delimited string into a list (caveat)?

问题描述

我需要能够接受这样的字符串:

'''foo, bar, "一，二"，三四'''

进入:

['foo', 'bar', '一，二'，'三四']

我有一种感觉(来自#python 的提示)解决方案将涉及 shlex 模块.

解决方案

shlex 模块解决方案允许转义引号，一个引号转义另一个，以及 shell 支持的所有花哨的东西.

<预><代码>>>>进口shlex>>>my_splitter = shlex.shlex('''foo, bar, "一，二"，三四'''，posix=True)>>>my_splitter.whitespace += ','>>>my_splitter.whitespace_split = True>>>打印列表(my_splitter)['foo', 'bar', '一，二'，'三'，'四']

转义引号示例:

<预><代码>>>>my_splitter = shlex.shlex('''"test, a",'foo,bar",baz',bar xc3xa4 baz''',posix=真)>>>my_splitter.whitespace = ',' ;my_splitter.whitespace_split = True>>>打印列表(my_splitter)['test, a', 'foo,bar",baz', 'bar xc3xa4 baz']

I need to be able to take a string like:

'''foo, bar, "one, two", three four'''

into:

['foo', 'bar', 'one, two', 'three four']

I have an feeling (with hints from #python) that the solution is going to involve the shlex module.

解决方案

The shlex module solution allows escaped quotes, one quote escape another, and all fancy stuff shell supports.

>>> import shlex
>>> my_splitter = shlex.shlex('''foo, bar, "one, two", three four''', posix=True)
>>> my_splitter.whitespace += ','
>>> my_splitter.whitespace_split = True
>>> print list(my_splitter)
['foo', 'bar', 'one, two', 'three', 'four']

escaped quotes example:

>>> my_splitter = shlex.shlex('''"test, a",'foo,bar",baz',bar xc3xa4 baz''',
                              posix=True) 
>>> my_splitter.whitespace = ',' ; my_splitter.whitespace_split = True 
>>> print list(my_splitter)
['test, a', 'foo,bar",baz', 'bar xc3xa4 baz']

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