如何“扔"JSF2 404 错误? [英] How to "throw" JSF2 404 error?

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本文介绍了如何“扔"JSF2 404 错误?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

假设我有一个管理用户的应用程序.您可以添加新用户、删除它们、编辑详细信息等.每个用户都有一个 ID 并且在 URL 上有详细信息页面,如下所示:

Let's say that I have an application which manages users. You can add new user, delete them, edit detail etc. Each user has na ID and has detail page on URL like this:

..../user/detail.jsf?id=123

现在,如果 ID 为 123 的用户不存在怎么办?我认为自然反应将是 404 标准错误.与在 URL(如/user/dtail.jsf)中输入拼写错误时输出的完全相同.那么问题来了:有这种方法吗?

Now, what should happen if user with ID 123 does not exists? I think that natural reaction would be 404 standard error. Exactly the same as is outputed when you make some typo in URL (like /user/dtail.jsf). So the question is: is there such method?

或者这个反应 (404) 是否合适?

Or maybe is this reaction (404) appropriate?

谢谢.

推荐答案

只需将验证器附加到 id 视图参数,如果验证失败,则在响应中设置错误代码 404.

Just attach a validator to the id view parameter and if validation fails, set error code 404 on the response.

例如

考虑这个简单的 Facelet:

Consider this simple Facelet:

<html xmlns="http://www.w3.org/1999/xhtml"
    xmlns:h="http://java.sun.com/jsf/html"
    xmlns:f="http://java.sun.com/jsf/core">

    <f:metadata>
        <f:viewParam id="id" name="id" value="#{myBean.id}" validator="#{myBean.validate}"/>
    </f:metadata>

    <h:body>

        <h:outputText value="#{myBean.id}"/>

    </h:body>

</html>

以及以下支持 bean:

And the following backing bean:

@ManagedBean
@ViewScoped
public class MyBean {

    private Long id;

    public void validate(FacesContext context, UIComponent component, Object object) {
        // Do some validation
        // And if failed:
        context.getExternalContext().setResponseStatus(404);
        context.responseComplete();
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

}

这篇关于如何“扔"JSF2 404 错误?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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