如何处理 webView URL 上的 intent://? [英] How to handle intent:// on a webView URL?

查看:15
本文介绍了如何处理 webView URL 上的 intent://?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我目前正在开发一个带有 webView 的 android 应用程序.在某些 urls 上,我需要使用 shouldOverrideUrlLoading 方法,该方法非常简单:

I'm currently developing an android app with a webView. On some urls I need to use the shouldOverrideUrlLoading method, which is pretty straight forward :

if(url.startsWith("something")){
//do something
return true;
}

我的问题:

某些 URLS,例如在 google 搜索中,具有以下 URL 方案:

Some URLS, on google search for example, have the following URL scheme :

intent://en.m.wikipedia.org/wiki/Test_cricket#Intent;scheme=http;package=org.wikipedia;S.browser_fallback_url=https%3A%2F%2Fwww.google.pt%2Fsearchurl%2Fr.html%23app%3Dorg.wikipedia%26pingbase%3Dhttps%3A%2F%2Fwww.google.pt%2F%26url%3Dhttps%3A%2F%2Fen.m.wikipedia.org%2Fwiki%2FTest_cricket;S.android.intent.extra.REFERRER_NAME=https%3A%2F%2Fwww.google.pt;launchFlags=0x8080000;end

我试过使用:

Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
startActivity(browserIntent);

但我有一个错误:

10-15 15:18:15.546: W/System.err(29086): android.content.ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.VIEW dat=intent://en.m.wikipedia.org/wiki/Test_cricket }

我应该如何处理这种 URL 方案?

How should I handle this kind of URL scheme ?

更新:

根据@CommonsWare 的评论,我尝试在 Intent 上使用 parseUri()URL 创建一个 Intent 对象 然后尝试 startActivity(),类似于:

Following @CommonsWare comments, I've tried using parseUri() on Intent to create an Intent object from the URL and then try startActivity(), something like:

Intent myIntent = new Intent().parseUri(url, Intent.URI_INTENT_SCHEME);
startActivity(myIntent);

但我仍然得到:

android.content.ActivityNotFoundException: No Activity found to handle Intent { act=android.intent.action.VIEW dat=http://en.m.wikipedia.org/wiki/Test_cricket flg=0x8080000 pkg=org.wikipedia (has extras) }

我的指令可能有误,或者我根本无法按照@CommonsWare 指定的方式构建intent.关于如何构建 Intent 的任何提示?

I may have got the instructions wrong or I'm simply unable to construct the intent as @CommonsWare specified. Any tips on how to construct the Intent?

推荐答案

这里描述了这个 Intent url 的结构 https://developer.chrome.com/multidevice/android/intents.

Structure of this intent url is described here https://developer.chrome.com/multidevice/android/intents.

所以我们可以像这样在内部 WebView 中处理它:

So we can handle it in internal WebView like this:

@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
    if (url.startsWith("intent://")) {
        try {
            Context context = view.getContext();
            Intent intent = Intent.parseUri(url, Intent.URI_INTENT_SCHEME);

            if (intent != null) {
                view.stopLoading();

                PackageManager packageManager = context.getPackageManager();
                ResolveInfo info = packageManager.resolveActivity(intent, PackageManager.MATCH_DEFAULT_ONLY);
                if (info != null) {
                    context.startActivity(intent);
                } else {
                    String fallbackUrl = intent.getStringExtra("browser_fallback_url");
                    view.loadUrl(fallbackUrl);

                    // or call external broswer
//                    Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(fallbackUrl));
//                    context.startActivity(browserIntent);
                }

                return true;
            }
        } catch (URISyntaxException e) {
            if (GeneralData.DEBUG) {
                Log.e(TAG, "Can't resolve intent://", e);
            }
        }
    }

    return false;
}

这篇关于如何处理 webView URL 上的 intent://?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆