使用 Cypher 复制不同类型的关系 [英] Copy relationships of different type using Cypher

问题描述

我想将现有关系复制到新节点.所有节点都已经存在，我想将所有传入关系复制到第二个节点.给定一个节点 D 和一个像

I want to copy existing relationships to a new node. All nodes exist already and I would like to copy all incoming relationships to a second node. Given a node D and a graph like

A -[r]-> B <-[s]- C

我想在单个 Cypher 查询中创建以下内容:

I would like to create the following in a single Cypher query:

A -[r]-> B <-[s]- C
A -[r]-> D <-[s]- C

仅应创建第二行中的关系，因为所有其他节点都已存在.我尝试了以下 Cypher 查询(这是一个无效查询(不知道如何从此类型中提取参数:org.neo4j.kernel.impl.core.RelationshipProxy)):

Only the relationships in the second line should be created, as all other nodes exist already. I have tried the following Cypher query (which is an Invalid query (Don't know how to extract parameters from this type: org.neo4j.kernel.impl.core.RelationshipProxy)):

START targetNode = node(42)
MATCH sourceNode -[r]-> targetNode
CREATE sourceNode -[s:TYPE(r)]-> targetNode
RETURN s

推荐答案

目前没有任何好的方法可以做到这一点.这是一个非常合理的用例，所以我鼓励你在这里提出一个问题:https://github.com/neo4j/community/issues

There doesn't exist any good way to do this today. It's a very reasonable use case though, so I would encourage you to raise an issue about it here: https://github.com/neo4j/community/issues

感谢分享！

安德烈斯

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