在 HIVE 中删除一系列分区 [英] Dropping a range of partitions in HIVE

问题描述

我有一个按列日期分区的 Hive(版本 0.11.0)表，类型为字符串.我想知道在 Hive 中是否存在一种方法可以删除一系列日期的分区(例如从date1"到date2").我尝试了以下(SQL 类型)查询，但它们的语法似乎不正确:

I have a Hive (ver 0.11.0) table partitioned by column date, of type string. I want to know if there exists a way in Hive by which I can drop partitions for a range of dates (say from 'date1' to 'date2'). I have tried the following (SQL type) queries, but they don't seem to be syntactically correct:

ALTER TABLE myTable DROP IF EXISTS PARTITION
(date>='date1' and date<='date2');

ALTER TABLE myTable DROP IF EXISTS PARTITION
(date>='date1' && date<='date2');

ALTER TABLE myTable DROP IF EXISTS PARTITION
(date between 'date1' and 'date2');

推荐答案

我试过这个语法很有效.

I tried this syntax it worked.

ALTER TABLE mytable DROP PARTITION (dates>'2018-04-14',dates<'2018-04-16');

命令输出:

    Dropped the partition dates=2018-04-15/country_id=107
    Dropped the partition dates=2018-04-15/country_id=110
    Dropped the partition dates=2018-04-15/country_id=112
    Dropped the partition dates=2018-04-15/country_id=14
    Dropped the partition dates=2018-04-15/country_id=157
    Dropped the partition dates=2018-04-15/country_id=159
    Dropped the partition dates=2018-04-15/country_id=177
    Dropped the partition dates=2018-04-15/country_id=208
    Dropped the partition dates=2018-04-15/country_id=22
    Dropped the partition dates=2018-04-15/country_id=233
    Dropped the partition dates=2018-04-15/country_id=234
    Dropped the partition dates=2018-04-15/country_id=76
    Dropped the partition dates=2018-04-15/country_id=83
    OK
    Time taken: 0.706 seconds

我正在使用，Hive 1.2.1000.2.5.5.0-157

I am using, Hive 1.2.1000.2.5.5.0-157

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