失败，异常 java.io.IOException:org.apache.avro.AvroTypeException: Found long,期待在 hive 中的联合 [英] Failed with exception java.io.IOException:org.apache.avro.AvroTypeException: Found long, expecting union in hive

问题描述

需要帮助！！！

我正在使用 flume 将 twitter 提要流式传输到 hdfs 并将其加载到 hive 中进行分析.

I am streaming twitter feeds into hdfs using flume and loading it up in hive for analysis.

步骤如下:

hdfs 中的数据:

我已经在 avsc 文件中描述了 avro schema 并将其放入 hadoop:

I have described the avro schema in an avsc file and put it in hadoop:

 {"type":"record",
 "name":"Doc",
 "doc":"adoc",
 "fields":[{"name":"id","type":"string"},
       {"name":"user_friends_count","type":["int","null"]},
       {"name":"user_location","type":["string","null"]},
       {"name":"user_description","type":["string","null"]},
       {"name":"user_statuses_count","type":["int","null"]},
       {"name":"user_followers_count","type":["int","null"]},
       {"name":"user_name","type":["string","null"]},
       {"name":"user_screen_name","type":["string","null"]},
       {"name":"created_at","type":["string","null"]},
       {"name":"text","type":["string","null"]},
       {"name":"retweet_count","type":["boolean","null"]},
       {"name":"retweeted","type":["boolean","null"]},
       {"name":"in_reply_to_user_id","type":["long","null"]},
       {"name":"source","type":["string","null"]},
       {"name":"in_reply_to_status_id","type":["long","null"]},
       {"name":"media_url_https","type":["string","null"]},
       {"name":"expanded_url","type":["string","null"]}]}

我已经编写了一个 .hql 文件来创建一个表并在其中加载数据:

I have written an .hql file to create a table and loaded data in it:

 create table tweetsavro
    row format serde
        'org.apache.hadoop.hive.serde2.avro.AvroSerDe'
    stored as inputformat
        'org.apache.hadoop.hive.ql.io.avro.AvroContainerInputFormat'
    outputformat
        'org.apache.hadoop.hive.ql.io.avro.AvroContainerOutputFormat'
    tblproperties ('avro.schema.url'='hdfs:///avro_schema/AvroSchemaFile.avsc');

    load data inpath '/test/twitter_data/FlumeData.*' overwrite into table tweetsavro;

我已成功运行 .hql 文件，但是当我在 hive 中运行 select *from <tablename> 命令时，它显示以下错误:

I have successfully run the .hql file but when i run the select *from <tablename> command in hive it shows the following error:

错误

tweetsavro 的输出是:

The output of tweetsavro is:

hive> desc tweetsavro;
OK
id                      string                                      
user_friends_count      int                                         
user_location           string                                      
user_description        string                                      
user_statuses_count     int                                         
user_followers_count    int                                         
user_name               string                                      
user_screen_name        string                                      
created_at              string                                      
text                    string                                      
retweet_count           boolean                                     
retweeted               boolean                                     
in_reply_to_user_id     bigint                                      
source                  string                                      
in_reply_to_status_id   bigint                                      
media_url_https         string                                      
expanded_url            string                                      
Time taken: 0.697 seconds, Fetched: 17 row(s)

推荐答案

我遇到了完全相同的问题.该问题存在于时间戳字段(在您的案例中为created_at"列)中，我试图将其作为字符串插入到我的新表中.我的假设是这些数据在我的源代码中采用 [ "null","string"] 格式.我分析了从 sqoop import --as-avrodatafile 进程生成的源 avro 模式.从导入生成的 avro 架构的时间戳列具有以下签名.
<代码>{"name": "order_date",类型":[空"，长"]，默认":空，"columnName": "order_date",sqlType":93"},

I was facing the exact same issue. The issue existed in the timestamp field("created_at" column in your case) which i was trying to insert as string into my new table. My assumption was this data would be in [ "null","string"] format in my source. I analyzed the source avro schema which got generated from the sqoop import --as-avrodatafile process. The avro schema generated from import had the below signature for the timestamp column.
{ "name" : "order_date", "type" : [ "null", "long" ], "default" : null, "columnName" : "order_date", "sqlType" : "93" },

SqlType 93 代表时间戳数据类型.所以在我的目标表 Avro Schema 文件中，我将数据类型更改为long"，这解决了问题.我的猜测可能是您的某一列中的数据类型不匹配.

SqlType 93 stands for Timestamp datatype. So in my target table Avro Schema file I changed the data type to 'long' and this solved the issue. My guess is possibly the mismatch of datatype in one of your columns.

这篇关于失败，异常 java.io.IOException:org.apache.avro.AvroTypeException: Found long,期待在 hive 中的联合的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！