Backbone.js 模型与集合 [英] Backbone.js model with collection
问题描述
我有 2 个模型和一个系列.JobSummary
是一个模型,JobSummaryList
是 JobSummary
项的集合,然后我有一个 JobSummarySnapshot
模型,其中包含一个 JobSummaryList
:
I have 2 models and one collection. JobSummary
is a model, JobSummaryList
is a collection of JobSummary
items, and then I have a JobSummarySnapshot
model that contains a JobSummaryList
:
JobSummary = Backbone.Model.extend({});
JobSummaryList = Backbone.Collection.extend({
model: JobSummary
});
JobSummarySnapshot = Backbone.Model.extend({
url: '/JobSummaryList',
defaults: {
pageNumber: 1,
summaryList: new JobSummaryList()
}
});
当我在 JobSummarySnapshot
对象上调用 fetch
时,它获取所有内容......除了当我在 summaryList
集合中移动时,它们都是类型为 object
而不是 JobSummary
.
When I call fetch
on the JobSummarySnapshot
object, it gets everything... Except when I move through the summaryList
collection they are all of type object
and not JobSummary
.
我认为这是有道理的,因为除了 defaults
对象,它不知道 summaryList
应该是 JobSummaryList
类型.我可以浏览每个项目并将其转换为 JobSummary
对象,但我希望有一种方法可以做到这一点,而无需手动进行.
I suppose this makes sense since other than the defaults
object, it doesn't know that the summaryList
should be of type JobSummaryList
. I can go through each item and convert it to a JobSummary
object, but I was hoping there was a way to do it without having to do it manually.
这是我的测试代码(在 jsfiddle here 中工作):
Here's my test code (working jsfiddle here):
var returnData = {
pageNumber: 3,
summaryList: [
{
id: 5,
name: 'name1'},
{
id: 6,
name: 'name2'}
]
};
var fakeserver = sinon.fakeServer.create();
fakeserver.respondWith('GET', '/JobSummaryList', [200,
{
'Content-Type': 'application/json'},
JSON.stringify(returnData)]);
var callback = sinon.spy();
var summarySnapshot = new JobSummarySnapshot();
summarySnapshot.bind('change', callback);
summarySnapshot.fetch();
fakeserver.respond();
var theReturnedList = callback.getCall(0).args[0].attributes.summaryList;
_.each(theReturnedList, function(item) {
console.log('Original Item: ');
console.log(item instanceof JobSummary); // IS FALSE
var convertedItem = new JobSummary(item);
console.log('converted item: ');
console.log(convertedItem instanceof JobSummary); // IS TRUE
});
更新:我突然想到我可以覆盖 parse 函数并以这种方式设置它......我现在有了这个:
UPDATE: It occurred to me that I could override the parse function and set it that way... I have this now:
JobSummarySnapshot = Backbone.Model.extend({
url: '/JobSummaryList',
defaults: {
pageNumber: 1,
summaryList: new JobSummaryList()
},
parse: function(response) {
this.set({pageNumber: response.pageNumber});
var summaryList = new JobSummaryList();
summaryList.add(response.summaryList);
this.set({summaryList: summaryList});
}
});
到目前为止这有效.如果有人对此发表评论,请保留问题....
This works so far. Leaving the question open in case someone has comment on it....
推荐答案
你的 parse()
函数不应该 set()
任何东西,更好的做法是返回属性,Backbone 将负责设置它.例如
Your parse()
function shouldn't set()
anything, its a better practice to just return the attributes, Backbone will take care of setting it. e.g.
parse: function(response) {
response.summaryList = new JobSummaryList(response.summaryList);
return response;
}
无论你从 parse()
返回什么都是 传递给set()
.
Whatever you return from parse()
is passed to set()
.
不返回任何东西(就像返回undefined
)和调用set(undefined)
是一样的,这可能会导致它没有通过验证,或者其他一些意想不到的如果您的自定义 validate()
/set()
方法期望获得一个对象,则结果.如果您的验证或 set()
方法因此失败,则传递给 Backbone.Model#fetch()
的 options.success
回调将不会'不叫.
Not returning anything (which is like returning undefined
) is the same as calling set(undefined)
, which could cause it not to pass validation, or some other unexpected results if your custom validate()
/set()
methods expects to get an object. If your validation or set()
method fails because of that, the options.success
callback passed to Backbone.Model#fetch()
won't be called.
此外,为了使这更通用,以便 set()
从其他地方(不仅是从服务器响应)到普通对象也会影响它,您可能想要覆盖 set()
代替:
Also, to make this more generic, so that set()
ing to a plain object from other places (and not only from the server response) also effects it, you might want to override set()
instead:
set: function(attributes, options) {
if (attributes.summaryList !== undefined && !(attributes.summaryList instanceof JobSummaryList)) {
attributes.summaryList = new JobSummaryList(attributes.summaryList);
}
return Backbone.Model.prototype.set.call(this, attributes, options);
}
您可能还会发现 Backbone-relational 很有趣 - 它可以更轻松地处理集合/models 嵌套在模型中.
You might also find Backbone-relational interesting - it makes it much easier to deal with collections/models nested inside models.
编辑我忘记从set()方法返回,代码现在更新
edit I forgot to return from the set() method, the code is now updated
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