如何按名称从 res/raw 读取文件 [英] How to read file from res/raw by name

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本文介绍了如何按名称从 res/raw 读取文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想打开文件夹 res/raw/ 中的文件.我绝对确定该文件存在.打开我试过的文件

I want to open a file from the folder res/raw/. I am absolutely sure that the file exists. To open the file I have tried

File ddd = new File("res/raw/example.png");

命令

ddd.exists(); 

产生.所以这个方法行不通.

yields FALSE. So this method does not work.

尝试

MyContext.getAssets().open("example.png");

以 getMessage() "null" 结束异常.

简单地使用

R.raw.example

是不可能的,因为文件名仅在运行时作为字符串被知道.

is not possible because the filename is only known during runtime as a string.

为什么访问/res/raw/文件夹中的文件如此困难?

Why is it so difficult to access a file in the folder /res/raw/ ?

推荐答案

在给定链接的帮助下,我能够自己解决问题.正确的方法是用

With the help of the given links I was able to solve the problem myself. The correct way is to get the resource ID with

getResources().getIdentifier("FILENAME_WITHOUT_EXTENSION",
                             "raw", getPackageName());

将其作为 InputStream 获取

To get it as a InputStream

InputStream ins = getResources().openRawResource(
            getResources().getIdentifier("FILENAME_WITHOUT_EXTENSION",
            "raw", getPackageName()));

这篇关于如何按名称从 res/raw 读取文件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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