我的 Google oAuth2 令牌看起来正确吗? [英] Does my Google oAuth2 Token look right?
问题描述
我正在编写 Web 服务器以支持 Google API 的 oAuth2,并且正在关注 本文档.在我尝试使用访问令牌制作 Google API 之前,一切似乎都运行良好.来自文档的示例调用:
I am programming a web server to support oAuth2 for Google APIs and am following this documentation. Everything seems to be working fine up to the point where I try to make a Google API using the Access Token. Example call from the documentation:
https://www.googleapis.com/oauth2/v1/userinfo?access_token=1/fFBGRNJru1FQd44AzqT3Zg
当我用我的访问令牌尝试它时,我收到 401 invalid token 错误.
When I try it with my access token I get 401 invalid token error.
翻阅文献,所有示例都以 1/fFBGR...... 格式显示访问令牌.我的访问令牌的格式为 ya29.AHES67z....... 并且更长(请参阅下面包含来自 google 的响应的片段).
Looking through the literature, all examples show the Access Token in format 1/fFBGR....... My Access Token is of form ya29.AHES67z....... and is much longer (see the snippet below containing response from google).
oauth2 request:{
"access_token" : "ya29.AHES67zeEn-RDg9CA5gGKMLKuG4uVB7W4O4WjNr-NBfY6Dtad4vbIZ",
"token_type" : "Bearer",
"expires_in" : 3600
}
所以看起来我的令牌不正确.我必须编码/解码它吗?
So it appears my token is incorrect. Do I have to encode/decode it?
推荐答案
我最近一直在玩 VBA 的 OAuth2.0.
I've been recently playing around with OAuth2.0 from VBA.
Authorization Code Begins With: 4/Omoy (30 Characters Long)
Access_Token Begins With: ya29.AHES (60 Characters Long)
Refresh_Token Begins With: 1/Ry68 (45 Characters Long)
我无需进行任何解码或编码即可使用这些值.这些都是有效的、功能性的价值.
I didn't have to do any decoding or encoding to use these values. These were working, functional values.
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