我怎样才能从我的Razor视图内部进行检查ModelState.IsValid [英] How can I check ModelState.IsValid from inside my Razor view
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问题描述
我在我的操作方法如下:
如果(!ModelState.IsValid)
返回查看(VM);
在视图我想不是present一个提交键,以便删除如果模型状态无效。有没有一种方法,我可以做到这一点?在视图中提供模型状态?
更新:我根据我得到的答案实现这样的:
< DIV CLASS =adm_td0的风格=填充:0;>
@if(ViewData.ModelState.IsValid){
<输入类型=提交值=删除NAME ='SubmitAction/>
}
<输入类型=提交值=取消NAME ='SubmitAction/>
< / DIV>
解决方案
在视图中可用的模型状态?
块引用>当然:
@if(!ViewData.ModelState.IsValid)
{
< DIV>有一些错误< / DIV>
}I have the following in my action method:
if (!ModelState.IsValid) return View(vm);
In the view I want to not present a submit key to allow deletion if the model state is not valid. Is there a way that I can do this? Is model state available in the view?
Update: I have implemented this based on the answers I was given:
<div class="adm_td0" style=" padding: 0;"> @if (ViewData.ModelState.IsValid) { <input type='submit' value='Delete' name='SubmitAction' /> } <input type='submit' value='Cancel' name='SubmitAction' /> </div>
解决方案Is model state available in the view?
Of course:
@if (!ViewData.ModelState.IsValid) { <div>There are some errors</div> }
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