__init__() 得到了一个意外的关键字参数“用户" [英] __init__() got an unexpected keyword argument 'user'

问题描述

我正在使用 Django 创建用户和创建用户时的对象.但是有一个错误

i am using Django to create a user and an object when the user is created. But there is an error

__init__() 得到一个意外的关键字参数 'user'

调用 view.py 中的 register() 函数时.功能是:

when calling the register() function in view.py. The function is:

def register(request):  
    '''signup view'''     
    if request.method=="POST":  
        form=RegisterForm(request.POST)  
        if form.is_valid():  
            username=form.cleaned_data["username"]  
            email=form.cleaned_data["email"]  
            password=form.cleaned_data["password"]  
            user=User.objects.create_user(username, email, password)  
            user.save()
            return HttpResponseRedirect('/keenhome/accounts/login/')
        else: 
            form = RegisterForm()      
            return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))  

    #This is used for reinputting if failed to register    
    else: 
        form = RegisterForm()      
        return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))

对象类是:

class LivingRoom(models.Model):
    '''Living Room object'''
    user = models.OneToOneField(User)

    def __init__(self, temp=65):
        self.temp=temp

    TURN_ON_OFF = (
        ('ON', 'On'),
        ('OFF', 'Off'),
    )

    TEMP = (
        ('HIGH', 'High'),
        ('MEDIUM', 'Medium'),
        ('LOW', 'Low'),
    )

    on_off = models.CharField(max_length=2, choices=TURN_ON_OFF)
    temp = models.CharField(max_length=2, choices=TEMP)

#signal function: if a user is created, add control livingroom to the user    
def create_control_livingroom(sender, instance, created, **kwargs):
    if created:
        LivingRoom.objects.create(user=instance)

post_save.connect(create_control_livingroom, sender=User)

Django 错误页面通知错误信息:user=User.objects.create_user(用户名、电子邮件、密码)和LivingRoom.objects.create(user=instance)

The Django error page notifies the error information: user=User.objects.create_user(username, email, password) and LivingRoom.objects.create(user=instance)

我试图搜索这个问题，找到了一些案例，但仍然不知道如何解决它.

I tried to search this problem, finding some cases, but still cannot figure out how to solve it.

推荐答案

你做不到

LivingRoom.objects.create(user=instance)

因为您有一个 __init__ 方法，它不以 user 作为参数.

because you have an __init__ method that does NOT take user as argument.

你需要类似的东西

#signal function: if a user is created, add control livingroom to the user    
def create_control_livingroom(sender, instance, created, **kwargs):
    if created:
        my_room = LivingRoom()
        my_room.user = instance

更新

但是，由于 bruno 有 已经说过了，Django的models.Model子类的初始化器最好不要管，或者应该接受*args和**kwargs 匹配模型的元字段.

But, as bruno has already said it, Django's models.Model subclass's initializer is best left alone, or should accept *args and **kwargs matching the model's meta fields.

所以，遵循更好的原则，你可能应该有类似的东西

So, following better principles, you should probably have something like

class LivingRoom(models.Model):
    '''Living Room object'''
    user = models.OneToOneField(User)

    def __init__(self, *args, temp=65, **kwargs):
        self.temp = temp
        return super().__init__(*args, **kwargs)

注意 - 如果您没有使用 temp 作为关键字参数，例如LivingRoom(65)，那么你必须开始这样做.LivingRoom(user=instance, temp=66) 或者如果您想要默认值 (65)，只需 LivingRoom(user=instance) 即可.

Note - If you weren't using temp as a keyword argument, e.g. LivingRoom(65), then you'll have to start doing that. LivingRoom(user=instance, temp=66) or if you want the default (65), simply LivingRoom(user=instance) would do.

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