如何在django中将文件流式传输到客户端 [英] how to stream file to client in django

问题描述

我想知道如何使用 django 将数据流式传输到客户端.

I want to know how can I stream data to client using django.

目标

用户提交一个表单，表单数据被传递给一个返回一个字符串的网络服务.字符串被压缩 (tar.gz) 并且 tarball 被发送回用户.

The user submits a form, the form data is passed to a web service which returns a string. The string is tarballed (tar.gz) and the tarball is sent back to the user.

我不知道是怎么回事.我搜索并找到了 this，但我只有一个字符串，我不知道是不是我想要的东西，我不知道用什么来代替 filename = __file__ ，因为我没有文件 - 只是一个字符串.如果我为每个用户创建一个新文件，这将不是一个好方法.所以请帮助我.(抱歉，我是网络编程新手).

I don't know what's the way. I searched and I found this, but I just have a string and I don't know if it is the thing I want, I don't know what to use in place of filename = __file__ , because I don't have file - just a string. If I create a new file for each user, this won't be a good way. so please help me. (sorry I'm new in web programming).

$('#sendButton').click(function(e) {
        e.preventDefault();
        var temp = $("#mainForm").serialize();
        $.ajax({
            type: "POST",
            data: temp,
            url: 'main/',
            success: function(data) {                
                $("#mainDiv").html(data.form);
                ????                

            }
        });
    });

我想使用ajax，那么我该怎么做才能成功使用ajac函数并返回视图.真的谢谢.

I want to use ajax, so what should i do in success of ajac function and in return of view. really thanks.

我的view.py:

def idsBackup(request):
    if request.is_ajax():        
        if request.method == 'POST':
           result = ""
           form = mainForm(request.POST)
           if form.is_valid():
               form = mainForm(request.POST)
               //do form processing and call web service               

                    string_to_return = webserviceString._result 
                    ???
           to_json = {}
           to_json['form'] = render_to_string('main.html', {'form': form}, context_instance=RequestContext(request))
           to_json['result'] = result
           ???return HttpResponse(json.dumps(to_json), mimetype='application/json')
        else:
            form = mainForm()
        return render_to_response('main.html', RequestContext(request, {'form':form}))
    else:
        return render_to_response("ajax.html", {}, context_instance=RequestContext(request))

推荐答案

您可以创建 ContentFile 使用字符串内容而不是实际文件，然后将其作为响应发送.

You can create a django file instance of ContentFile using a string content instead of actual file and then send it as a response.

示例代码:

from django.core.files.base import ContentFile
def your_view(request):
    #your view code
    string_to_return = get_the_string() # get the string you want to return.
    file_to_send = ContentFile(string_to_return)
    response     = HttpResponse(file_to_send,'application/x-gzip')
    response['Content-Length']      = file_to_send.size    
    response['Content-Disposition'] = 'attachment; filename="somefile.tar.gz"'
    return response   

这篇关于如何在django中将文件流式传输到客户端的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！