如何在ASP.NET MVC 4 HTML5表单操作链接到控制器的ActionResult方法 [英] How to link HTML5 form action to Controller ActionResult method in ASP.NET MVC 4
问题描述
我有,我想通过调用视图的关联控制器的
类。这里是以下HTML5 code为以下形式:的ActionResult
的方法来处理表单内按钮的基本形式
< H2>欢迎及LT; / H>< DIV> < H3>登录和LT; / H3 GT&; <形式方法=邮报行动=<! - 发生的事情在这里 - > >
用户名:其中;输入类型=文本名称=用户名/> < BR />
密码:LT;输入类型=文本名称=密码/> < BR />
<输入类型=提交值=登陆GT&;
<输入类型=提交值=创建帐户/>
< /表及GT;< / DIV><! - 更多code ... - >
对应的控制器
code是以下内容:
[HttpPost]
公众的ActionResult MyAction(字符串输入,采集的FormCollection)
{
开关(输入)
{
案登录:
//做一些东西...
打破;
案创建帐户
//做一些其他的东西...
打破;
} 返回查看();
}
您使用的HTML帮助,并有
@using(Html.BeginForm())
{
用户名:其中;输入类型=文本名称=用户名/> < BR />
密码:LT;输入类型=文本名称=密码/> < BR />
<输入类型=提交值=登陆GT&;
<输入类型=提交值=创建帐户/>
}
或使用URL帮手
<形式方法=邮报行动=@ Url.Action(MyAction,myController的)>
Html.BeginForm
有几个(13)覆盖在那里你可以指定更多的信息,例如,正常使用时,使用文件上传:
@using(Html.BeginForm(myaction,myController的,FormMethod.Post,新{ENCTYPE =的multipart / form-data的}))
{
< ...>
}
如果您不指定任何参数, Html.BeginForm()
将创建一个 POST
的形式, 指向当前的控制器和动作电流即可。举个例子,假设你有一个名为控制器帖子
,并呼吁行动删除
公众的ActionResult删除(INT ID)
{
VAR模型= db.GetPostById(ID);
返回查看(模型);
}[HttpPost]
公众的ActionResult删除(INT ID)
{
VAR模型= db.GetPostById(ID);
如果(型号!= NULL)
db.DeletePost(ID); 返回RedirectToView(「指数」);
}
和你的HTML页面会是这样:
< H2>的你确定要删除<?/ H2>
< P>该帖子命名为<强> @ Model.Title< / STRONG>将被删除&下; / P>@using(Html.BeginForm())
{
<输入类型=提交级=BTN BTN-危险值=删除邮报/>
<文字和GT;或< /文字和GT;
@ Url.ActionLink(走地名录,索引)
}
I have a basic form for which I want to handle buttons inside the form by calling the ActionResult
method in the View's associated Controller
class. Here is the following HTML5 code for the form:
<h2>Welcome</h2>
<div>
<h3>Login</h3>
<form method="post" action= <!-- what goes here --> >
Username: <input type="text" name="username" /> <br />
Password: <input type="text" name="password" /> <br />
<input type="submit" value="Login">
<input type="submit" value="Create Account"/>
</form>
</div>
<!-- more code ... -->
The corresponding Controller
code is the following:
[HttpPost]
public ActionResult MyAction(string input, FormCollection collection)
{
switch (input)
{
case "Login":
// do some stuff...
break;
case "Create Account"
// do some other stuff...
break;
}
return View();
}
you make the use of the HTML Helper and have
@using(Html.BeginForm())
{
Username: <input type="text" name="username" /> <br />
Password: <input type="text" name="password" /> <br />
<input type="submit" value="Login">
<input type="submit" value="Create Account"/>
}
or use the Url helper
<form method="post" action="@Url.Action("MyAction", "MyController")" >
Html.BeginForm
has several (13) overrides where you can specify more information, for example, a normal use when uploading files is using:
@using(Html.BeginForm("myaction", "mycontroller", FormMethod.Post, new {enctype = "multipart/form-data"}))
{
< ... >
}
If you don't specify any arguments, the Html.BeginForm()
will create a POST
form that points to your current controller and current action. As an example, let's say you have a controller called Posts
and an action called Delete
public ActionResult Delete(int id)
{
var model = db.GetPostById(id);
return View(model);
}
[HttpPost]
public ActionResult Delete(int id)
{
var model = db.GetPostById(id);
if(model != null)
db.DeletePost(id);
return RedirectToView("Index");
}
and your html page would be something like:
<h2>Are you sure you want to delete?</h2>
<p>The Post named <strong>@Model.Title</strong> will be deleted.</p>
@using(Html.BeginForm())
{
<input type="submit" class="btn btn-danger" value="Delete Post"/>
<text>or</text>
@Url.ActionLink("go to list", "Index")
}
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