是否支持非泛型类中的泛型构造函数? [英] Is generic constructor in non-generic class supported?

问题描述

是不是不支持，是不是支持但是我要搞点花样?

Is it not supported, is it supported but I have to do some tricks?

示例:

class Foo
{
  public Foo<T1,T2>(Func<T1,T2> f1,Func<T2,T1> f2)
  {
     ...
  }
}

泛型仅在构造函数中使用，没有依赖于它们的字段/属性，我使用它(泛型)来强制 f1 和 f2 的类型相关.

the generics are only used in constructor, there is no field/property depended on them, I use it (generics) to enforce the type correlation for f1 and f2.

备注:我找到了解决方法 -- 静态方法 Create，但无论如何我很好奇为什么我的直接方法有问题.

Remark: I found the workaround -- static method Create, but anyway I am curious why I have problem with straightforward approach.

推荐答案

不，泛型或非泛型类都不支持泛型构造函数.同样，不支持通用事件、属性和终结器.

No, generic constructors aren't supported in either generic or non-generic classes. Likewise generic events, properties and finalizers aren't supported.

只是偶尔我同意它会很方便 - 但语法看起来很糟糕.例如，假设您有:

Just occasionally I agree it would be handy - but the syntax would look pretty awful. For example, suppose you had:

public class Foo<T> {}

public class Foo
{
    public Foo<T>() {}
}

什么会

new Foo<string>()

做什么?调用非泛型类的泛型构造函数，还是泛型类的普通构造函数?你必须以某种方式区分它们，这会很混乱:(

do? Call the generic constructor of the non-generic class, or the normal constructor of the generic class? You'd have to differentiate between them somehow, and it would be messy :(

同样，考虑泛型类中的泛型构造函数:

Likewise, consider a generic constructor in a generic class:

public class Foo<TClass>
{
    public Foo<TConstructor>() {}
}

你会如何调用构造函数?希望我们都同意:

How would you call the constructor? Hopefully we can all agree that:

new Foo<string><int>()

太丑了...

所以，是的，从语义上讲，它偶尔会有用 - 但不幸的是，由此产生的丑陋抵消了这一点.

So yes, semantically it would be occasionally useful - but the resulting ugliness counterbalances that, unfortunately.

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