强制 GSON 使用特定的构造函数 [英] Force GSON to use specific constructor
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问题描述
public class UserAction {
private final UUID uuid;
private String userId;
/* more fields, setters and getters here */
public UserAction(){
this.uuid = UUID.fromString(new com.eaio.uuid.UUID().toString());
}
public UserAction(UUID uuid){
this.uuid = uuid;
}
@Override
public boolean equals(Object obj) {
if (obj == null) {
return false;
}
if (getClass() != obj.getClass()) {
return false;
}
final UserAction other = (UserAction) obj;
if (this.uuid != other.uuid && (this.uuid == null || !this.uuid.equals(other.uuid))) {
return false;
}
return true;
}
@Override
public int hashCode() {
int hash = 7;
hash = 53 * hash + (this.uuid != null ? this.uuid.hashCode() : 0);
return hash;
}
}
我正在使用 Gson 对这个类进行序列化和反序列化.今天我不得不在这个对象中添加一个最终的 UUID.我没有问题序列化.我需要强制 gson 在反序列化时使用 public UserAction(UUID uuid)
构造函数.我怎样才能做到这一点?
I am using Gson to serilize and deserialize this class. As today I had to add a final UUID in this object. I have no problem serializing. I need to force gson to use public UserAction(UUID uuid)
constructor when deserializing. How can I achieve that ?
推荐答案
您可以实现自定义 JsonDeserializer 并将其注册到 GSON.
You could implement a custom JsonDeserializer and register it with GSON.
class UserActionDeserializer implements JsonDeserializer<UserAction> {
public UserAction deserialize(JsonElement json, Type typeOfT,
JsonDeserializationContext context) throws JsonParseException {
return new UserAction(UUID.fromString(json.getAsString());
}
GsonBuilder gson = new GsonBuilder();
gson.registerTypeAdapter(UserAction.class, new UserActionDeserializer());
请记住,此代码尚未经过测试.
Bear in mind that this code has not been tested.
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