按日期分组，当 count() 不产生任何行时为 0 [英] Grouping by date, with 0 when count() yields no lines

问题描述

我正在使用 Postgresql 9，当没有计算任何行时，我正在努力进行计数和分组.

I'm using Postgresql 9 and I'm fighting with counting and grouping when no lines are counted.

让我们假设以下架构:

create table views {
 date_event timestamp with time zone ;
 event_id integer;
}

让我们想象以下内容:

2012-01-01 00:00:05    2
2012-01-01 01:00:05    5
2012-01-01 03:00:05    8
2012-01-01 03:00:15    20

我想按小时分组，并计算行数.我希望我可以检索以下内容:

I want to group by hour, and count the number of lines. I wish I could retrieve the following :

2012-01-01 00:00:00    1
2012-01-01 01:00:00    1
2012-01-01 02:00:00    0
2012-01-01 03:00:00    2
2012-01-01 04:00:00    0
2012-01-01 05:00:00    0
.
.

2012-01-07 23:00:00    0

我的意思是，对于每个时间范围槽，我计算表中日期对应的行数，否则，我返回一个计数为零的行.

I mean that for each time range slot, I count the number of lines in my table whose date correspond, otherwise, I return a line with a count at zero.

以下肯定行不通(只会对计数行 > 0 的行发出声音).

The following will definitely not work (will yeld only lines with counted lines > 0).

SELECT  extract ( hour from date_event ),count(*)
FROM views
where date_event > '2012-01-01' and date_event <'2012-01-07'
GROUP BY extract ( hour from date_event );

请注意，我可能还需要按分钟、小时、天、月或年分组(当然可以进行多个查询).

Please note I might also need to group by minute, or by hour, or by day, or by month, or by year (multiple queries is possible of course).

我只能使用普通的旧 sql，而且由于我的视图表可能非常大(> 100M 记录)，我尽量记住性能.

I can only use plain old sql, and since my views table can be very big (>100M records), I try to keep performance in mind.

如何实现?

谢谢！

推荐答案

鉴于表中没有日期，您需要一种方法来生成它们.您可以使用 generate_series 函数:

Given that you don't have the dates in the table, you need a way to generate them. You can use the generate_series function:

SELECT * FROM generate_series('2012-01-01'::timestamp, '2012-01-07 23:00', '1 hour') AS ts;

这将产生如下结果:

         ts          
---------------------
 2012-01-01 00:00:00
 2012-01-01 01:00:00
 2012-01-01 02:00:00
 2012-01-01 03:00:00
...
 2012-01-07 21:00:00
 2012-01-07 22:00:00
 2012-01-07 23:00:00
(168 rows)

剩下的任务是使用这样的外连接来连接两个选择:

The remaining task is to join the two selects using an outer join like this :

select extract ( day from ts ) as day, extract ( hour from ts ) as hour,coalesce(count,0) as count from 
(
    SELECT  extract ( day from date ) as day , extract ( hour from date ) as hr ,count(*)
    FROM    sr
    where date>'2012-01-01' and date <'2012-01-07'
    GROUP BY   extract ( day from date ) , extract ( hour from date )
) AS cnt 
 right outer join ( SELECT * FROM generate_series ( '2012-01-01'::timestamp, '2012-01-07 23:00', '1 hour') AS ts ) as dtetable on extract ( hour from ts ) = cnt.hr and extract ( day from ts ) = cnt.day 
 order by day,hour asc;

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