删除 android parse.com 上的重复安装 [英] Delete duplicate installation on android parse.com

问题描述

我正在尝试在 android 上重新安装时删除重复的安装.我正在从 ParseInstallation 获取查询，但它不起作用.

I'm trying delete duplicate installation when reinstall on android. I'm doing get query from ParseInstallation but it is not working.

我在下面附上我的代码:

I attach my code below:

public boolean checkDuplicate(String id, ParseInstallation installation){




    ParseQuery<ParseInstallation> query = ParseInstallation.getQuery();
    query.whereEqualTo("userId", id);
    query.findInBackground(new FindCallback<ParseInstallation>() {
        public void done(List<ParseInstallation> list, ParseException e) {
            if (e == null) {

                //Log.d("LISTA-CHECKDUPLICATE", "id " + list.size() );
                for(int i = 0; i<list.size(); i++){
                    try {
                        list.get(i).delete();
                    } catch (ParseException e1) {
                        // TODO Auto-generated catch block
                        e1.printStackTrace();
                    }
                }

            } else {
                Log.d("LISTA-CHECKDUPLICATE", "Error: " + e.getMessage());
            }
        }
    });


    return false;

}

推荐答案

最后我用云代码解决了这个问题，并在android上调用了这个函数:

Finally I solved this with cloud code and calling this function on android:

Parse.Cloud.define("checkDuplicado", function(request, response) {
    Parse.Cloud.useMasterKey();
    var query = new Parse.Query(Parse.Installation);
    var objectId = request.params.objectId;
    query.equalTo("userId", request.params.userId);
    query.first().then(function(duplicate) {
        if (typeof duplicate === "undefined" ) {
            console.log("Duplicate does not exist,New installation");
            response.success("Nueva Instalacion");
        } else if(duplicate.id != objectId){
            console.log("Duplicado existe..Intentando borrar " + duplicate.id );
            //console.log("userId-NUEVO " + request.object.get("userId") + " ID: " + request.object.id);
           // console.log("userId-DUPLICADO " + duplicate.get("userId") + " ID: "+ duplicate.id);
            duplicate.destroy().then(function(duplicate) {
                console.log("Duplicado borrado correctamente");
                response.success("Duplicado borrado correctamente");
            }, function() {
                console.log(error.code + " " + error.message);
                response.success("Error Borrando duplicado");
            });

           response.success("Check duplicados realizado correctamente");
        }
        else{
            response.success("Check duplicados realizado correctamente");
        }
    }, function(error) {
        console.warn(error.code + error.message);
        response.success("Error");
    });
    });

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