Lua 成对出现,顺序和它写的一样 [英] Lua in pairs with same order as it's written
问题描述
有没有什么办法可以像下面这样的表格按照写入的顺序循环遍历?
Is there any way to loop trough a table like the one below in the same order as it's written?
local tbl = {
["hello"] = 1,
[2] = 2,
[50] = 3,
["bye"] = 4,
[200] = 5
}
我的意思是,当我使用成对"时,每次执行我的代码时都会得到不同的顺序......
What I mean is that when I use "in pairs" I'll get a different order everytime I execute my code ...
我正在寻找这样的东西:
I'm searching for something like this:
function get_keys(tbl)
local rtable = {}
for k,v in pairs(tbl) do
table.insert(rtable, k)
end
return rtable
end
local keys_of_tbl = get_keys(tbl)
for i = 1, table.getn(keys_of_tbl) do
--Do something with: tbl[keys_of_tbl[i]]
end
但是因为函数get_keys"再次基于成对",它不起作用......
But because the function "get_keys" is based on "in pairs" again, it won't work ...
推荐答案
在 Lua 中,pair 遍历键的顺序是未指定的.但是,您可以保存在数组样式表中添加项目的顺序并使用 ipairs
(它具有用于迭代数组中的键的定义顺序).为此,您可以使用元表创建自己的有序表,以便在添加新键时保持键顺序.
In Lua, the order that pairs iterates through the keys is unspecified. However you can save the order in which items are added in an array-style table and use ipairs
(which has a defined order for iterating keys in an array). To help with that you can create your own ordered table using metatables so that the key order will be maintained when new keys are added.
EDIT(较早的代码在更新时插入了密钥的多个副本)
EDIT (earlier code inserted multiple copies of the key on updates)
要做到这一点,您可以使用 __newindex
,只要索引尚未添加到表中,我们就会调用它.ordered_add
方法更新、删除或存储隐藏表_keys
和_values
中的键.请注意 __newindex
在我们更新键时也将始终被调用,因为我们没有将值存储在表中而是将它存储在隐藏"表中 _keys
和_values
.
To do this you can use __newindex
which we be called so long as the index is not added yet to the table. The ordered_add
method updates, deletes, or stores the key in the hidden tables _keys
and _values
. Note that __newindex
will always be called when we update the key too since we didn't store the value in the table but instead stored it in the "hidden" tables _keys
and _values
.
但是请注意,我们不能在此表中使用任何键,键名 "_keys"
将覆盖我们的隐藏表,因此更安全的替代方法是使用 ordered_table.insert(t,key, value)
ordered_table.index(t, key)
和 ordered_table.remove(t, key)
方法.
Note however that we cannot use any key in this table, the key name "_keys"
will overwrite our hidden table so the safer alternative is to use the ordered_table.insert(t, key, value)
ordered_table.index(t, key)
and ordered_table.remove(t, key)
methods.
ordered_table = {}
function ordered_table.insert(t, k, v)
if not rawget(t._values, k) then -- new key
t._keys[#t._keys + 1] = k
end
if v == nil then -- delete key too.
ordered_table.remove(t, k)
else -- update/store value
t._values[k] = v
end
end
local function find(t, value)
for i,v in ipairs(t) do
if v == value then
return i
end
end
end
function ordered_table.remove(t, k)
local v = t._values[k]
if v ~= nil then
table.remove(t._keys, find(t._keys, k))
t._values[k] = nil
end
return v
end
function ordered_table.index(t, k)
return rawget(t._values, k)
end
function ordered_table.pairs(t)
local i = 0
return function()
i = i + 1
local key = t._keys[i]
if key ~= nil then
return key, t._values[key]
end
end
end
function ordered_table.new(init)
init = init or {}
local t = {_keys={}, _values={}}
local n = #init
if n % 2 ~= 0 then
error"in ordered_table initialization: key is missing value"
end
for i=1,n/2 do
local k = init[i * 2 - 1]
local v = init[i * 2]
if t._values[k] ~= nil then
error("duplicate key:"..k)
end
t._keys[#t._keys + 1] = k
t._values[k] = v
end
return setmetatable(t,
{__newindex=ordered_table.insert,
__len=function(t) return #t._keys end,
__pairs=ordered_table.pairs,
__index=t._values
})
end
--- Example Usage:
local t = ordered_table.new{
"hello", 1, -- key, value pairs
2, 2,
50, 3,
"bye", 4,
200, 5
}
print(#t)
print("hello is", t.hello)
print()
for k, v in pairs(t) do --- Lua 5.2 __pairs metamethod
print(k, v)
end
t.bye = nil -- delete that
t[2] = 7 -- use integer keys
print(#t)
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