使用 Lua 将 0 秒格式化为 00:00:00 [英] Using Lua to format 0 seconds as 00:00:00

问题描述

我正在尝试将持续时间(以秒为单位)格式化为时间，并且我得到的结果表明我应该在某处考虑一个纪元.我希望 os.date("%X", 0) 产生00:00:00"但它返回20:00:00"以及日期值12/31/69"(不过我不需要日历日期).

I'm trying to format a duration (in seconds) as a time and I'm getting results indicating that I'm supposed to account for an epoch somewhere. I expected os.date("%X", 0) to produce "00:00:00" but it is returning "20:00:00" as well as a date value of "12/31/69" (I don't need a calendar date though).

是否有一种标准方法可以获取一个持续时间字符串，该字符串会导致 0 秒产生一个代表总零秒的时钟?我似乎无法在任何地方找到我正在尝试做的事情的示例.

Is there a standard way of getting a time duration string that causes 0 seconds to produce a clock representing a total of zero seconds? I can't seem to find an example anywhere of what I'm trying to do.

谢谢

推荐答案

在大多数系统(即 POSIX)中，os.date("%X",0) 给你时间纪元，即 00:00:00(协调世界时，UTC)，1970 年 1 月 1 日.你得到 20:00:00 因为你在不同的时区.

In most systems (ie, POSIX), os.date("%X",0) gives you the time of the epoch, which is 00:00:00 (Coordinated Universal Time, UTC), 1 January 1970. You get 20:00:00 because you're in a different time zone.

要强制使用 UTC 而不是您的时区，请以 ! 开头.手册中提到了这一点.

To force UTC instead of your time zone, start the format with !. This is mentioned in the manual.

因此，根据需要使用 os.date("!%X",0) 获取 00:00:00 .它可以在少于一天 (86400) 的任何秒数内工作.例如，os.date("!%X",70) 给出 00:01:10:1 分 10 秒.

So, use os.date("!%X",0) to get 00:00:00 as desired. It'll work with any number of seconds less than a day (86400). For instance, os.date("!%X",70) gives 00:01:10: 1 minute and 10 seconds.

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