Socket.IO 处理断开事件 [英] Socket.IO handling disconnect event

问题描述

无法处理这个断开连接事件，不知道为什么socket没有发送到客户端/客户端没有响应！

Can't handle this disconnect event, don't know why socket is not sent to the client / client doesn't respond!

服务器

io.sockets.on('connection', function (socket) {

  socket.on('NewPlayer', function(data1) {

    online = online + 1;
    console.log('Online players : ' + online);
    console.log('New player connected : ' + data1);
    Players[data1] = data1;
    console.log(Players);

  });

  socket.on('DelPlayer', function(data) {

    delete Players[data];
    console.log(Players);
    console.log('Adios' + data);

  });

  socket.on('disconnect', function () {

      socket.emit('disconnected');
      online = online - 1;

  });

});

客户

 var socket = io.connect('http://localhost');

    socket.on('connect', function () { 

        person_name = prompt("Welcome. Please enter your name");

        socket.emit('NewPlayer', person_name);

        socket.on('disconnected', function() {

            socket.emit('DelPlayer', person_name);

        });

    });

如您所见，当客户端断开连接时，Array 对象 [person_name] 应该被删除，但事实并非如此.

As you can see when a client disconnects the Array object[person_name] should be deleted, but it's not.

推荐答案

好的，不是通过名称来识别玩家，而是使用他们连接的套接字来识别玩家.你可以有一个像

Ok, instead of identifying players by name track with sockets through which they have connected. You can have a implementation like

var allClients = [];
io.sockets.on('connection', function(socket) {
   allClients.push(socket);

   socket.on('disconnect', function() {
      console.log('Got disconnect!');

      var i = allClients.indexOf(socket);
      allClients.splice(i, 1);
   });
});

希望这能帮助你换个角度思考

Hope this will help you to think in another way

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