Android socket.io 切换活动不丢失连接 [英] Android socket.io switch activities without lost connection

查看:12
本文介绍了Android socket.io 切换活动不丢失连接的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我开发了一个游戏,将使用socket.io连接,我的服务器是用node js编写的,我的android客户端使用socket.io,现在,我想问你的问题是:

I developed a game, which will be use socket.io connection, my server is writing in node js, and my android client use socket.io, and now, my question for You is:

如何在不与服务器断开连接的情况下切换活动,我至少有 4 个活动、聊天、游戏视图、在线玩家列表等等.

how can I switch activities without lost connection with server, i have minimum 4 activities, chat, game view, online players list and more.

当我打开我的应用程序时,我创建了连接,当我登录到服务器时,我想将活动切换到另一个.

When i turn on my app, I create connection, and when I log in to server i would like to switch activity to another.

有什么建议吗?

推荐答案

尝试做一个单例类的SocketIO服务

try to make a singleton class SocketIO service

在第一个活动中初始化 socketio 连接以建立与服务器的连接,这里是我的示例服务类

initialize socketio connection at first activity to establish your connection to server, here my example service class

    public class SocketIOClient {
    private static final String serverUrl = "http://example-socket-server.jit.su";
    private static SocketIO socket;
    private static SocketIOClient instance;
    private static Activity act;
    private static String id;

    public SocketIOClient() {
    }

    public static void initInstance(String uid) throws MalformedURLException {
        if (instance == null) {
            instance = new SocketIOClient();
            instance.initID(uid);
            if (SocketIOClient.getSocket() == null) {
                SocketIOClient.setSocket(new SocketIO());
            }
            SocketIOClient.connectIO();
        }
    }

    public static void setActivity(Activity a) {
        SocketIOClient.act = a;
    }

    public static SocketIO getSocket() {
        return socket;
    }

    public static void setSocket(SocketIO socket) {
        SocketIOClient.socket = socket;
    }

    public String getId() {
        return id;
    }

    private void initID(String uid) {
        if (SocketIOClient.id == null) {
            SocketIOClient.id = uid;
        }
    }

    public static void connectIO() throws MalformedURLException {
        try {
            SocketIO.setDefaultSSLSocketFactory(SSLContext.getDefault());
        } catch (NoSuchAlgorithmException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }
        SocketIOClient.getSocket().connect(serverUrl, new IOCallback() {
            @Override
            public void onMessage(JSONObject json, IOAcknowledge ack) {
                // TODO Auto-generated method stub
            }

            @Override
            public void onMessage(String data, IOAcknowledge ack) {

            }

            @Override
            public void onError(SocketIOException socketIOException) {
            }

            @Override
            public void onDisconnect() {
                // TODO Auto-generated method stub

            }

            @Override
            public void onConnect() {

            }

            @Override
            public void on(String event, IOAcknowledge ack, Object... args) {

            }
        });
    }

    public static void emit(String event, Object args)
            throws MalformedURLException {
        if (SocketIOClient.getSocket().isConnected() == false) {
            SocketIOClient.getSocket().reconnect();
        }
        SocketIOClient.getSocket().emit(event, args);
    }

    public static void emitWithAcknowledge(String event, Object args)
            throws MalformedURLException {
        if (SocketIOClient.getSocket().isConnected() == false) {
            SocketIOClient.getSocket().reconnect();
        }
        SocketIOClient.getSocket().emit(event, new IOAcknowledge() {

            @Override
            public void ack(Object... args) {
                // TODO Auto-generated method stub

            }
        }, args);
    }

}

在第一个活动中,我输入了以下代码:

at the first activity i put this code:

SocketIOClient.initInstance(android_id);

它是创建对象并尝试连接到服务器,如果你想要事件或其他东西,你可以在 onConnect 或 onDisconnect 处理它

it's create object and try connect to server, you can handle it at onConnect or onDisconnect if you want event or something

当你切换活动时,你仍然连接到服务器,如果你想关闭你的连接,请使用这个:

when you switching activities, you're still connected to server and if you want to close your connection use this :

SocketIOClient.getSocket().disconnect();

这篇关于Android socket.io 切换活动不丢失连接的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆