Android socket.io 切换活动不丢失连接 [英] Android socket.io switch activities without lost connection
问题描述
我开发了一个游戏,将使用socket.io连接,我的服务器是用node js编写的,我的android客户端使用socket.io,现在,我想问你的问题是:
I developed a game, which will be use socket.io connection, my server is writing in node js, and my android client use socket.io, and now, my question for You is:
如何在不与服务器断开连接的情况下切换活动,我至少有 4 个活动、聊天、游戏视图、在线玩家列表等等.
how can I switch activities without lost connection with server, i have minimum 4 activities, chat, game view, online players list and more.
当我打开我的应用程序时,我创建了连接,当我登录到服务器时,我想将活动切换到另一个.
When i turn on my app, I create connection, and when I log in to server i would like to switch activity to another.
有什么建议吗?
推荐答案
尝试做一个单例类的SocketIO服务
try to make a singleton class SocketIO service
在第一个活动中初始化 socketio 连接以建立与服务器的连接,这里是我的示例服务类
initialize socketio connection at first activity to establish your connection to server, here my example service class
public class SocketIOClient {
private static final String serverUrl = "http://example-socket-server.jit.su";
private static SocketIO socket;
private static SocketIOClient instance;
private static Activity act;
private static String id;
public SocketIOClient() {
}
public static void initInstance(String uid) throws MalformedURLException {
if (instance == null) {
instance = new SocketIOClient();
instance.initID(uid);
if (SocketIOClient.getSocket() == null) {
SocketIOClient.setSocket(new SocketIO());
}
SocketIOClient.connectIO();
}
}
public static void setActivity(Activity a) {
SocketIOClient.act = a;
}
public static SocketIO getSocket() {
return socket;
}
public static void setSocket(SocketIO socket) {
SocketIOClient.socket = socket;
}
public String getId() {
return id;
}
private void initID(String uid) {
if (SocketIOClient.id == null) {
SocketIOClient.id = uid;
}
}
public static void connectIO() throws MalformedURLException {
try {
SocketIO.setDefaultSSLSocketFactory(SSLContext.getDefault());
} catch (NoSuchAlgorithmException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
SocketIOClient.getSocket().connect(serverUrl, new IOCallback() {
@Override
public void onMessage(JSONObject json, IOAcknowledge ack) {
// TODO Auto-generated method stub
}
@Override
public void onMessage(String data, IOAcknowledge ack) {
}
@Override
public void onError(SocketIOException socketIOException) {
}
@Override
public void onDisconnect() {
// TODO Auto-generated method stub
}
@Override
public void onConnect() {
}
@Override
public void on(String event, IOAcknowledge ack, Object... args) {
}
});
}
public static void emit(String event, Object args)
throws MalformedURLException {
if (SocketIOClient.getSocket().isConnected() == false) {
SocketIOClient.getSocket().reconnect();
}
SocketIOClient.getSocket().emit(event, args);
}
public static void emitWithAcknowledge(String event, Object args)
throws MalformedURLException {
if (SocketIOClient.getSocket().isConnected() == false) {
SocketIOClient.getSocket().reconnect();
}
SocketIOClient.getSocket().emit(event, new IOAcknowledge() {
@Override
public void ack(Object... args) {
// TODO Auto-generated method stub
}
}, args);
}
}
在第一个活动中,我输入了以下代码:
at the first activity i put this code:
SocketIOClient.initInstance(android_id);
它是创建对象并尝试连接到服务器,如果你想要事件或其他东西,你可以在 onConnect 或 onDisconnect 处理它
it's create object and try connect to server, you can handle it at onConnect or onDisconnect if you want event or something
当你切换活动时,你仍然连接到服务器,如果你想关闭你的连接,请使用这个:
when you switching activities, you're still connected to server and if you want to close your connection use this :
SocketIOClient.getSocket().disconnect();
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