Bigquery - 结构体格式 [英] Bigquery- Struct format
本文介绍了Bigquery - 结构体格式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
WITH yourTable AS (
SELECT 1 AS id, '2013,1625,1297,7634' AS string_col UNION ALL
SELECT 2, '1,2,3,4,5'
)
SELECT id,
(SELECT ARRAY_AGG(CAST(num AS INT64))
FROM UNNEST(SPLIT(string_col)) AS num
) AS num,
ARRAY(SELECT CAST(num AS INT64)
FROM UNNEST(SPLIT(string_col)) AS num
) AS num_2
FROM yourTable
这就是我的实际表的设计方式,现在我想乘以 num*num_2,然后再求和.有没有办法把它变成像 ID、nums.num、nums.num_2 这样的结构格式,这样我就可以简单地乘以得到必要的结果.
This is how exactly my actual table is designed and Now I would like to multiply num*num_2 and then later sum it up. Is there a way to get this into struct format like ID, nums.num,nums.num_2 so that I can simply multiply which gives me the necessary result.
PS:我在上面的 select 语句中寻找解决方案,但不在with"语句中.
PS: I am looking for solution in the select statement above but not within "with" statement.
推荐答案
好吧,假设你真的有理由按照你的方式拥有你的桌子(见我对你的问题的评论) - 下面应该工作
Ok, assuming that you really have reason to have your table the way you have (see my comment on your question) - below should work
#standardSQL
SELECT id,
(
SELECT SUM(num * num_2)
FROM (SELECT pos, num FROM UNNEST(num) num WITH OFFSET pos) a
JOIN (SELECT pos_2, num_2 FROM UNNEST(num_2) num_2 WITH OFFSET pos_2) b
ON a.pos = b.pos_2
) mul
FROM yourTable
你可以用下面的测试它
#standardSQL
WITH yourTable AS (
SELECT 1 id, [2013,1625,1297,7634] num, [2013,1625,1297,7634] num_2 UNION ALL
SELECT 2, [1,2,3,4,5], [1,2,3,4,5]
)
SELECT id,
(
SELECT SUM(num * num_2)
FROM (SELECT pos, num FROM UNNEST(num) num WITH OFFSET pos) a
JOIN (SELECT pos_2, num_2 FROM UNNEST(num_2) num_2 WITH OFFSET pos_2) b
ON a.pos = b.pos_2
) mul
FROM yourTable
这篇关于Bigquery - 结构体格式的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文