ansible - 结合三个字典列表 [英] ansible - combine three lists of dictionaries

问题描述

在我的剧本中，我从多个来源收集有关应用程序的事实，最终得到 3 个(或更多)列表，每个列表都有一个字典.

In my playbook I'm gathering facts on applications, from multiple sources and end up with 3 (or more) lists, each of them have a dict.

有没有办法将这种结构组合成一个字典列表.如果没有，关于我需要如何更改数据结构的任何建议?

Is there a way to combine such structure into one list of dictionaries. If not, any suggestion on how I would need to change the data structure?

我的代码试图结合 2 list-of-dict(即使在最终用例中也会有 3 个或更多).

My code that tries to combine 2 list-of-dict (even that in final usecase there would be 3 or more).

所有的war_*列表都应该有相同数量的字典，键为app_name"，我们随意选择war_time作为迭代器——而且app_name在其中是通用的

All war_* lists should have the same number of dictionaries, with key "app_name", just arbitrarily we choose war_time as iterator - and app_name is common among them all

- hosts: localhost
  vars:
    war_status:
    - app_name: app1-SNAPSHOT
      app_status: running
    - app_name: app2
      app_status: stopped
    - app_name: app3-jsf
      app_status: unknown

    war_time:
    - app_name: app1-SNAPSHOT
      app_time: '2017-07-07 06:38:30'
    - app_name: app2
      app_time: '2018-07-19 09:16:57'
    - app_name: app3-jsf
      app_time: '2019-07-21 06:00:57'

    war_proxy_status:
    - app_name: app1-SNAPSHOT
      app_where_found: inst1
    - app_name: app2
      app_where_found: inst2
    - app_name: app3-jsf
      app_where_found: inst3

  tasks:

  - set_fact:
      war_combined: []

  - name: combine1 war_status and war_time
    set_fact:
      war_combined: "{{ war_combined | default([]) + [ war_status | combine( item ) ] }}"
    loop: "{{ war_time }}"

  - debug:
      msg: "{{ war_combined }}"

我想达到的结果是:

war_combined:
- app_name: app1-SNAPSHOT
  app_status: running
  app_time: '2017-07-07 06:38:30'
  app_where_found: inst1
- app_name: app2
  app_status: stopped
  app_time: '2018-07-19 09:16:57'
  app_where_found: inst2
- app_name: app3-jsf
  app_status: unknown
  app_time: '2019-07-21 06:00:57'
  app_where_found: inst3

推荐答案

您应该组合单个元素，但您尝试将单个项目合并到整个列表中.

You should combine individual elements, but you try merge single item into whole list.

像这样:

- set_fact:
    war_combined: >-
      {{ war_combined | default([])
         + [item | combine(time_item) | combine(proxy_item)]
      }}
  vars:
    time_item: >-
      {{ war_time
         | selectattr('app_name','equalto',item['app_name'])
         | list
         | first
      }}
    proxy_item: >-
      {{ war_proxy_status
         | selectattr('app_name','equalto',item['app_name'])
         | list
         | first
      }}
  loop: "{{ war_status }}"

我们遍历 war_status 并使用辅助变量 time_item 和 proxy_item 对每次迭代进行评估，从带有 的列表中选择特定元素app_name 匹配当前项目的app_name.

We loop over war_status and use helper variables time_item and proxy_item that are evaluated for each iteration selecting specific element from lists with app_name matching current item's app_name.

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