如何在 flex 盒中淡入淡出? [英] how fade in a flex box?

问题描述

如何在淡入之前让弹性框不成为页面的一部分?我曾经用'display:0;'来做到这一点然后使用 jQuery .fadeIn().但是现在如果我将 display 设置为 0，当我淡入时，我当然会失去盒子的弹性.如果我使用 jQuery 将显示设置为 flex，那么它只会出现，而不是淡入.

HTML

<div class="flex-item-popup";id=弹出窗口"><div class="close"><i class="fa fa-2x fa-times-circle"</i></div><h2></h2><div class='text'></div><div class="videos"></div><div class="flex-container images"></div>

CSS

#popupContainer {位置:绝对；左:0；顶部:0；宽度:100%；高度:100%；显示:弹性；弹性方向:行；flex-wrap: 包裹;对齐内容:居中；对齐内容:flex-start；对齐项目:居中；z-索引:15；}

jQuery

$(document).ready(function() {//???});

解决方案

看起来有点奇怪，但是你可以做的是在 css 中，将其设置为 display: none.然后诀窍是在你的jquery中将 display 设置为 flex 然后再次隐藏它，然后 fadeIn:

CSS:

#popupContainer {/* ... */显示:无；弹性方向:行；flex-wrap: 包裹;/* ... */}

JS:

$("#popupContainer").css(显示"，弹性").隐藏().淡入();

这是有效的，因为 fadeIn() 会将项目设置回其以前的非隐藏 display 值.因此，设置 flex 并重新隐藏它会将此默认值"设置为重新设置.

http://jsfiddle.net/z2kxyjcq/1/

$("#popupContainer").css(显示"，弹性").隐藏().fadeIn(2000);

#popupContainer {位置:绝对；左:0；顶部:0；宽度:100%；高度:100%；显示:无；弹性方向:行；flex-wrap: 包裹;对齐内容:居中；对齐内容:flex-start；对齐项目:居中；z-索引:15；背景颜色:红色；}#popupContainer *{边框:1px纯蓝色；背景颜色:白色；}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script><div class="" id="popupContainer"><div class="flex-item-popup" id="popup"><div class="close"><i class="fa fa-2x fa-times-circle">1</i></div><h2>2</h2><div class='text'>a</div><div class="videos">b</div><div class="flex-container images">c</div>

How do I get a flex box to not be part of the page until I fade it in? I used to do this with 'display: 0;' and then use jQuery .fadeIn(). But now if I set display to 0, when I fade it in, of course I lose the flex-iness of the box. If I use jQuery to set display to flex, then it will just appear, not fade in.

HTML

<div class="" id="popupContainer">
    <div class="flex-item-popup" id="popup">
        <div class="close"><i class="fa fa-2x fa-times-circle"></i></div>
        <h2></h2>
        <div class='text'></div>
        <div class="videos"></div>
        <div class="flex-container images"></div>
    </div>
</div>

CSS

#popupContainer {
    position: absolute;
    left: 0;
    top: 0;
    width: 100%;
    height: 100%;
    display:flex;
    flex-direction: row;
    flex-wrap: wrap;
    justify-content: center;
    align-content: flex-start;
    align-items: center;
    z-index: 15;
}

jQuery

$(document).ready(function() {
    //???
});

解决方案

It seems a bit odd, but what you can do is in the css, set it to display: none. Then the trick is to set the display to flex in your jquery and then hide it again, then fadeIn:

CSS:

#popupContainer {
    /* ... */

    display:none;
    flex-direction: row;
    flex-wrap: wrap;

    /* ... */
}

JS:

$("#popupContainer")
    .css("display", "flex")
    .hide()
    .fadeIn();

This works because fadeIn() will set the item back to its previous non-hidden display value. So setting flex and re-hiding it will set this "default" for it to be set back to.

http://jsfiddle.net/z2kxyjcq/1/

$("#popupContainer")
    .css("display", "flex")
    .hide()
    .fadeIn(2000);

#popupContainer {
    position: absolute;
    left: 0;
    top: 0;
    width: 100%;
    height: 100%;
    display:none;
    flex-direction: row;
    flex-wrap: wrap;
    justify-content: center;
    align-content: flex-start;
    align-items: center;
    z-index: 15;
    background-color: red;
}
#popupContainer *{
    border: 1px solid blue;
background-color: white;    
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="" id="popupContainer">
<div class="flex-item-popup" id="popup">
    <div class="close"><i class="fa fa-2x fa-times-circle">1</i></div>
    <h2>2</h2>
    <div class='text'>a</div>
    <div class="videos">b</div>
    <div class="flex-container images">c</div>
</div>

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