C# 接口——只在其他接口中实现一个接口 [英] C# Interfaces- only implement an interface in other interfaces

问题描述

我只想在其他接口中实现某些接口，我不希望它们能够被类直接继承.

提前致谢！

解决方案

你不能在 C# 中这样做 - 任何类都可以实现它有权访问的任何接口.

你为什么要这样做?请记住，通过声明接口继承:

公共接口 InterfaceA {}公共接口 InterfaceB : InterfaceA {}

您指定任何实现 InterfaceB 的东西也必须实现 InterfaceA，所以无论如何你都会得到实现 InterfaceA 的类.

I would like to only implement certain interfaces within other interfaces, I don't want them to be able to be inherited directly by a class.

Thanks in advance!

解决方案

You can't do this in C# - any class can implement any interface it has access to.

Why would you want to do this? Bear in mind that by declaring an interface inheritance:

public interface InterfaceA {}
public interface InterfaceB : InterfaceA {}

You're specifying that anything implementing InterfaceB also has to implement InterfaceA, so you'll get classes implementing InterfaceA anyway.

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