使用“CASE WHEN"查询WHERE 中的语句导致 QuerySyntaxException:意外的 AST [英] Query using "CASE WHEN" statement in WHERE causes QuerySyntaxException: unexpected AST

问题描述

我正在尝试使用 Spring Data 进行查询，但无法使其工作:

I'm trying to make a query using Spring Data, but I cannot make it work:

@Query(SELECT t FROM Thing t WHERE name LIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >= :maxVal) END)
Page<Thing> getThings(@Param("name") String name, @Param("maxVal") int maxVal, @Param("minVal") minVal); 

堆栈跟踪:

引起:java.lang.IllegalArgumentException:org.hibernate.hql.internal.ast.QuerySyntaxException:意外的 AST节点:第 1 行第 49 列附近的 CASE [SELECT t FROM Thing t WHERE nameLIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <=:minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >=:maxVal) END] 在org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750)在org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677)在org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1683)在org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:331)在 sun.reflect.GeneratedMethodAccessor40.invoke(Unknown Source) 在sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)在 java.lang.reflect.Method.invoke(Method.java:606) 在org.springframework.orm.jpa.ExtendedEntityManagerCreator$ExtendedEntityManagerInvocationHandler.invoke(ExtendedEntityManagerCreator.java:334)在 com.sun.proxy.$Proxy83.createQuery(Unknown Source) 在org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:78)... 207 更多

Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: CASE near line 1, column 49 [SELECT t FROM Thing t WHERE name LIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >= :maxVal) END] at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1683) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:331) at sun.reflect.GeneratedMethodAccessor40.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:606) at org.springframework.orm.jpa.ExtendedEntityManagerCreator$ExtendedEntityManagerInvocationHandler.invoke(ExtendedEntityManagerCreator.java:334) at com.sun.proxy.$Proxy83.createQuery(Unknown Source) at org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:78) ... 207 more

原因:org.hibernate.hql.internal.ast.QuerySyntaxException:意外的 AST节点:第 1 行第 49 列附近的 CASE [SELECT t FROM Thing t WHERE nameLIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <=:minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >=:maxVal) END] 在org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91)在org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109)在org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:284)在org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:206)在org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158)在org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:126)在org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:88)在org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:190)在org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301)在org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236)在org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1800)在org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:328)

Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: CASE near line 1, column 49 [SELECT t FROM Thing t WHERE name LIKE :name AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END AND CASE WHEN (:maxVal <= 0) THEN TRUE ELSE (val >= :maxVal) END] at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91) at org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109) at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:284) at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:206) at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158) at org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:126) at org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:88) at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:190) at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301) at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236) at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1800) at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:328)

我使用它是因为我想至少使用五个过滤器进行更长的查询，并且我想简化进行过滤器组合进行不同查询的工作.

I'm using this because I want to make a longer query using five filters at least, and I want to simplify the effort of doing the filter combinations making differents querys.

不知道是否有不同(更好)的方式来做我想做的事，如果是的话很高兴听到.

Don't know if there is a different (and better) way to do what I want, glad to ear it if it is.

谢谢.

使用本机查询工作正常，但与分页不兼容...

Using native query works fine, but isn't compatible with pagination yet...

推荐答案

当 Hibernate 直接返回一个布尔值时，它似乎无法评估 CASE 表达式的结果.解决方法是使 CASE 表达式成为另一个表达式的一部分，例如通过将其与另一个布尔文字进行比较.

It looks like Hibernate cannot evaluate the result of a CASE expression when it returns a boolean literal directly. A workaround is to make the CASE expression part of another expression, e.g. by comparing it to another boolean literal.

所以代替:

... AND CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END

试试:

... AND (CASE WHEN (:minVal <= 0) THEN TRUE ELSE (val <= :minVal) END) = TRUE

但是看看那个表情，这样做会不会更简单:

But looking at that expression, wouldn't it be simpler to just do:

... AND (:minVal <= 0 OR val <= :minVal)

不是等价的吗?

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