在 swift 3.0 中从我的键盘扩展打开我的应用程序 [英] Open My application from my keyboard extension in swift 3.0

问题描述

我正在尝试从我的键盘扩展中打开.我有自定义键盘，并且已从设置中添加该键盘.在我的自定义键盘上有一个显示更多"按钮，我想点击这个按钮打开我的应用.

I am trying to open from my keyboard extension. I am having custom keyboard and I have add that keyboard from setting. On my custom keyboard there is one button "Show More", and I want to open my app on this button click.

所以我尝试了以下代码:

So I have tried following code :

let context = NSExtensionContext()
 context.open(url! as URL, completionHandler: nil)

 var responder = self as UIResponder?

 while (responder != nil) {

      if responder?.responds(to: Selector("openURL:")) == true {

           responder?.perform(Selector("openURL:"), with: url)
      }
      responder = responder!.next
 }

它运行成功，但正如我们在 swift 中所知 Selector("method_name:") 已被弃用并使用 #selector(classname.methodname(_:))相反，它发出警告.我想解决这个警告.所以我尝试过 Xcode 自动建议:

It is working successfully, but as we know in swift Selector("method_name:") is deprecated and use #selector(classname.methodname(_:)) instead so it is giving warning. And I want to solve that warning. So I have tried as Xcode automatically suggested :

 if responder?.responds(to: #selector(UIApplication.openURL(_:))) == true {

      responder?.perform(#selector(UIApplication.openURL(_:)), with: url)
 }

也试过:

 if responder?.responds(to: #selector(NSExtensionContext.open(_:))) == true {

      responder?.perform(#selector(NSExtensionContext.open(_:)), with: url)
 }

我也尝试了其他可能的方法，但没有运气.如果有人知道怎么做，请告诉我.

I have also tried others possible ways, but no luck. If anyone know how to do, please let me know.

我参考了这个链接，Julio Bailon 的回答:

I referred this link, Julio Bailon’s answer :

openURL 在 Action Extension 中不起作用

推荐答案

Swift 5.0:

打开托管应用程序的 Info.plist.

Open Info.plist of hosting app.

1. 添加网址类型 -> Item 0 -> Url Schemes -> Item 0 : "yourappname"
2. 添加Url Types -> Item 0 -> Url Schemes -> URL Identifier:你的包id"

转到键盘应用程序:

正确添加以下代码:

@objc func openURL(_ url: URL) {
       return
    }

    func openApp(_ urlstring:String) {

       var responder: UIResponder? = self as UIResponder
       let selector = #selector(openURL(_:))
       while responder != nil {
          if responder!.responds(to: selector) && responder != self {
             responder!.perform(selector, with: URL(string: urlstring)!)
             return
          }
          responder = responder?.next
        }
     }

调用:openApp("yourappname://your bundle id")

Call : openApp ("yourappname://your bundle id")

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