Django CSRF 验证失败.请求中止.- CSRF cookie 未设置 [英] Django CSRF verification failed. Request aborted.- CSRF cookie not set

问题描述

我知道以前有人问过这个问题.我已经尝试了人们给出的几乎所有选项，但我似乎无法解决它.我是一个完整的新手，所以请让我知道我哪里出错了.

我正在尝试编写一个简单的原始表单.到目前为止，我还没有实现任何身份验证或会话机制(但从我所读到的内容来看，这与此问题无关.如果我错了，请纠正我).

当我尝试提交表单时，出现以下错误:

禁止 (403)CSRF 验证失败.请求中止.给出的失败原因:未设置 CSRF cookie.

这是我的代码:

我的 Views.py 有这个方法:

def 提交(请求):全局字母数组菜肴 = Dish.objects.all().order_by('name')如果 request.method == "POST":打印请求.POST['餐厅']打印请求.POST['评级']render_to_response('index.html', {}, context_instance=RequestContext(request))别的:render_to_response('index.html', {}, context_instance=RequestContext(request))

许多人说使用 RequestContext 解决了这个问题，但对我来说，即使这样也行不通.

模板如下:

 
{% csrf_token %}<div class="form-group"><label for="">餐厅名称</label><input type="text" name="restaurant" class="form-control" id="">

<div class="form-group"><label for="">评分</label><select class="form-control" name="rating"><option>--</option><option>1(非常糟糕)</option><option>2(坏)</option><option>3(平均)</option><option>4(好)</option><option>5(优秀)</option></选择>

<button type="submit" class="btn btn-primary btn-block"><i class="fa fa-check-circle"></i>保存</表单>

settings.py 中的 middleware_classes 看起来像:

MIDDLEWARE_CLASSES = ('django.middleware.common.CommonMiddleware','django.contrib.sessions.middleware.SessionMiddleware','django.middleware.csrf.CsrfViewMiddleware','django.contrib.auth.middleware.AuthenticationMiddleware','django.contrib.messages.middleware.MessageMiddleware',)

django.middleware.csrf.CsrfViewMiddleware 在那里，它在 'django.contrib.sessions.middleware.SessionMiddleware' 下方

我的 url.py 有条目:

url(r'^admin/', include(admin.site.urls)),url(r'^index/$', 'testapp.views.index'),url(r'^starts_with/(?P.+)/dish/(?Pd+)/$', 'testapp.views.alphabet_dish'),url(r'^starts_with/(?P.+)/$', 'testapp.views.alphabet'),url(r'^submit/$', 'testapp.views.submit'),

我真的不确定这里有什么问题.正如我所说，我在这里阅读了类似的帖子，并尝试了回复中提到的所有内容.我错过了什么?我的浏览器是 Chrome，它接受 cookie.

解决方案

您的 CSRF 设置很好.问题是您没有返回结果.请记住，视图是一个函数.你需要 return render_to_response(...) 而不仅仅是调用它(这也是为什么通过删除 CSRF 你得到了 did not return an HttpResponse 错误)

除此之外，您正在做一些 Django 错误的常规操作:

• 不要使用 render_to_response(使用渲染).
• 不要重复
• 不要在 django 中使用全局变量.

因此:

def 提交(请求):# 全局字母数组菜肴 = Dish.objects.all().order_by('name')如果 request.method == "POST":打印请求.POST['餐厅']打印请求.POST['评级']返回渲染(请求，'index.html'，{})

I know this question has been asked before. I have tried almost all the options given by people but I cannot seem to solve it. I am a complete newbie so please let me know where I am going wrong.

I am trying to write a simple raw form. I have not implemented any authentication or session mechanism until now (but from what I have read that does not matter to this problem. Correct me if I am wrong).

When I try to submit my form, I get this error:

Forbidden (403)
CSRF verification failed. Request aborted.

Reason given for failure:
    CSRF cookie not set.

This is my code:

My Views.py has this method:

def submit(request):
    global alphabet_array
    dishes = Dish.objects.all().order_by('name')
    if request.method == "POST":
        print request.POST['restaurant']
        print request.POST['rating']
        render_to_response('index.html', {}, context_instance=RequestContext(request))
    else:
        render_to_response('index.html', {}, context_instance=RequestContext(request))

Many have said that using RequestContext solves this issue but for me even that is not working.

The template looks as below:

  <form role="form" action="/submit/" method="post">{% csrf_token %}
                <div class="form-group">
                  <label for="">Restaurant Name</label>
                  <input type="text" name="restaurant" class="form-control" id="">
                </div>
                <div class="form-group">
                  <label for="">Rating</label>
                  <select class="form-control" name="rating">
                    <option>--</option>
                    <option>1 (very bad)</option>
                    <option>2 (bad)</option>
                    <option>3 (average)</option>
                    <option>4 (good)</option>
                    <option>5 (excellent)</option>
                  </select>
                </div>
               <button type="submit" class="btn btn-primary btn-block"><i class="fa fa-check-circle"></i> Save</button>
    </form>

The middleware_classes in settings.py looks like:

MIDDLEWARE_CLASSES = (
    'django.middleware.common.CommonMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
)

django.middleware.csrf.CsrfViewMiddleware is there and it is below 'django.contrib.sessions.middleware.SessionMiddleware'

My url.py is has entries:

url(r'^admin/', include(admin.site.urls)),
    url(r'^index/$', 'testapp.views.index'),

    url(r'^starts_with/(?P<alphabet>.+)/dish/(?P<dish_id>d+)/$', 'testapp.views.alphabet_dish'),
    url(r'^starts_with/(?P<alphabet>.+)/$', 'testapp.views.alphabet'),
    url(r'^submit/$', 'testapp.views.submit'),

I am really not sure what is the problem here. As I said, I have read similar posts here and tried everything mentioned in the responses. What have I missed? My browser is Chrome and it is accepting cookies.

解决方案

Your CSRF setup is fine. The problem is you are not returning the result. Remember that the view is a function. You need to return render_to_response(...) not just call it (which is also why by removing CSRF you got the didn't return an HttpResponse error)

Other than that, you are doing a few general things that are django-ically wrong:

• Don't use render_to_response (use render).
• Don't repeat yourself.
• Don't use globals in django.

Hence:

def submit(request):
    # global alphabet_array
    dishes = Dish.objects.all().order_by('name')
    if request.method == "POST":
        print request.POST['restaurant']
        print request.POST['rating']

    return render(request, 'index.html', {})

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