如何遍历给定目录中的文件? [英] How can I iterate over files in a given directory?

问题描述

我需要遍历给定目录中的所有 .asm 文件并对它们执行一些操作.

I need to iterate through all .asm files inside a given directory and do some actions on them.

如何有效地做到这一点?

How can this be done in a efficient way?

推荐答案

上述答案的 Python 3.6 版本，使用 os - 假设您将目录路径作为 str 对象放在名为 directory_in_str 的变量中:

Python 3.6 version of the above answer, using os - assuming that you have the directory path as a str object in a variable called directory_in_str:

import os

directory = os.fsencode(directory_in_str)
    
for file in os.listdir(directory):
     filename = os.fsdecode(file)
     if filename.endswith(".asm") or filename.endswith(".py"): 
         # print(os.path.join(directory, filename))
         continue
     else:
         continue

或者递归地使用pathlib:

Or recursively, using pathlib:

from pathlib import Path

pathlist = Path(directory_in_str).glob('**/*.asm')
for path in pathlist:
     # because path is object not string
     path_in_str = str(path)
     # print(path_in_str)

• 使用rglob 将 glob('**/*.asm') 替换为 rglob('*.asm')
  • 这就像调用 Path.glob() 在给定的相对模式前添加 '**/' :

  from pathlib import Path
  
  pathlist = Path(directory_in_str).rglob('*.asm')
  for path in pathlist:
       # because path is object not string
       path_in_str = str(path)
       # print(path_in_str)
  

  ---

  原答案:

  ---

  Original answer:

  import os
  
  for filename in os.listdir("/path/to/dir/"):
      if filename.endswith(".asm") or filename.endswith(".py"): 
           # print(os.path.join(directory, filename))
          continue
      else:
          continue
  

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