在Java中获取目录及其子目录中的所有文件的非递归方式 [英] Non-recursive way to get all files in a directory and its subdirectories in Java

问题描述

我正在尝试获取目录及其子目录中所有文件的列表.我目前的递归方法如下:

I am trying to get a list of all files in a directory and its subdirectories. My current recursive approach is as follows:

private void printFiles(File dir) {
  for (File child : dir.listFiles()) {
    if (child.isDirectory()) {
      printFiles(child);
    } else if (child.isFile()) {
      System.out.println(child.getPath());
    }
  }
}

printFiles(new File("somedir/somedir2"));

但是，我希望有一种非递归方式(可能是现有的 API 调用)来执行此操作.如果没有，这是最干净的方法吗?

However, I was hoping there was a non-recursive way (an existing API call, maybe) of doing this. If not, is this the cleanest way of doing this?

推荐答案

您始终可以使用堆栈(对于 DFS)或队列(对于 BFS)将递归解决方案替换为迭代解决方案:

You can always replace a recursive solution with an iterative one by using a stack (for DFS) or a Queue (For BFS):

private void printFiles(File dir) {
  Stack<File> stack = new Stack<File>();
  stack.push(dir);
  while(!stack.isEmpty()) {
    File child = stack.pop();
    if (child.isDirectory()) {
      for(File f : child.listFiles()) stack.push(f);
    } else if (child.isFile()) {
      System.out.println(child.getPath());
    }
  }
}

printFiles(new File("abc/def.ghi"));

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