从单个源文件夹中 Gradle 多个 jars [英] Gradle multiple jars from single source folder
问题描述
至于现在,我们有一个名为 src
的单个源文件夹的项目结构,其中包含三个模块的源代码.我想做的是:
As for now we have a project structure with single source folder named src
, which contains source code for three modules. What I want to do is:
1) 编译源代码.这可以通过 sourceSets 定义轻松完成:
1) Compile source code. This is easily done with sourceSets definition:
sourceSets {
main {
java {
srcDir 'src'
}
}
}
2) 将编译结果放入三个jar中.我通过三个jar"类型的任务来做到这一点:
2) Put compilation results into three jars. I am doing this via three 'jar' type tasks:
我现在通过三个独立的任务来做到这一点:
I am doing this now via three separate tasks:
util.jar
util.jar
task utilJar(type: Jar) {
from(sourceSets.main.output) {
include "my/util/package/**"
}
}
client.jar
client.jar
task clientJar(type: Jar) {
from(sourceSets.main.output) {
include "my/client/package/**"
}
}
server.jar
server.jar
task serverJar(type: Jar) {
from(sourceSets.main.output) {
include "**"
}
excludes.addAll(utilJar.includes)
excludes.addAll(clientJar.includes)
}
问题是server.jar
应该包含所有未包含在client.jar
和util.jar
中的类.在 ant 构建脚本中,我们通过使用 difference
ant 任务来解决这个问题.这如何在 gradle 中完成(我目前的方法不起作用)?
The thing is that server.jar
should contain all classes that are not contained within client.jar
and util.jar
. In ant build script we solve this problem by using difference
ant task. How this can be done in gradle (my current approach doesn't work)?
也许我的方法是完全错误的.请指教.
Maybe my approach is completely wrong. Please advice.
附言至于现在我们不能改变项目源代码文件夹结构.
P.S. as for now we CAN NOT change the project source code folder structure.
推荐答案
我将在这里发布我的工作解决方案作为答案(我在 gradle 的论坛上得到了提示).
I will post my working solution here as an answer (I've got a hint on gradle's forum).
gradle 中的作用域非常奇怪:) 我认为每个任务定义都会创建某个Task"类的对象,在这种特殊情况下类似于JarTask".然后我可以从我的 build.gradle 脚本中的任何地方访问该类的任何属性.但是,我找到了唯一可以看到模式的地方,这些模式包含在 jar 文件中 - 在任务的 from
块内.所以我现在的工作解决方案是:
The scopes in gradle are very strange thing :) I thought that every task definition creates an object of some 'Task' class, which is something like 'JarTask' in this particular case. Then I can access any property of the class from anywhere in my build.gradle script. However, I found the only place where I can see the patterns, which are included in jar file - inside a from
block of a task. So my working solution for now is to:
1) 定义一个项目级集合以包含要从 server.jar
1) Define a project-level collection to contain patterns to be excluded from server.jar
2) 排除 serverJar
任务的 from
块中的所有模式.
2) Exclude all patterns in from
block of serverJar
task.
请看下面的最终版本
sourceSets {
main {
java {
srcDir 'src'
}
}
}
// holds classes included into client.jar and util.jar, so they are to be excluded from server.jar
ext.serverExcludes = []
// util.jar
task utilJar(type: Jar) {
from(sourceSets.main.output) {
include "my/util/package/**"
project.ext.serverExcludes.addAll(includes)
}
}
// client.jar
task clientJar(type: Jar) {
from(sourceSets.main.output) {
include "my/client/package/**"
project.ext.serverExcludes.addAll(includes)
}
}
// server.jar
task serverJar(type: Jar) {
from(sourceSets.main.output) {
exclude project.ext.serverExcludes
}
}
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