为什么 os.path.join() 在这种情况下不起作用? [英] Why doesn't os.path.join() work in this case?

问题描述

下面的代码不会加入，调试时命令不存储整个路径而只存储最后一个条目.

The below code will not join, when debugged the command does not store the whole path but just the last entry.

os.path.join('/home/build/test/sandboxes/', todaystr, '/new_sandbox/')

当我测试它时，它只存储代码的 /new_sandbox/ 部分.

When I test this it only stores the /new_sandbox/ part of the code.

推荐答案

后面的字符串不应以斜线开头.如果它们以斜线开头，则它们被视为绝对路径"，并且它们之前的所有内容都将被丢弃.

The latter strings shouldn't start with a slash. If they start with a slash, then they're considered an "absolute path" and everything before them is discarded.

引用 os.path 的 Python 文档.加入:

如果一个组件是绝对路径，则之前的所有组件都将被丢弃，并从绝对路径组件继续连接.

If a component is an absolute path, all previous components are thrown away and joining continues from the absolute path component.

注意在 Windows 上，与驱动器号相关的行为，与早期的 Python 版本相比似乎发生了变化:

Note on Windows, the behaviour in relation to drive letters, which seems to have changed compared to earlier Python versions:

在 Windows 上，当遇到绝对路径组件(例如，r'foo')时，不会重置驱动器号.如果一个组件包含驱动器号，则所有以前的组件都将被丢弃并重置驱动器号.请注意，由于每个驱动器都有一个当前目录，os.path.join("c:", "foo") 表示相对于驱动器 C:<上的当前目录的路径/code> (c:foo)，而不是 c:foo.

On Windows, the drive letter is not reset when an absolute path component (e.g., r'foo') is encountered. If a component contains a drive letter, all previous components are thrown away and the drive letter is reset. Note that since there is a current directory for each drive, os.path.join("c:", "foo") represents a path relative to the current directory on drive C: (c:foo), not c:foo.

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