如何从 WSL 中删除 Win10 的 PATH [英] How to remove the Win10's PATH from WSL

问题描述

我在 Win10 中使用 Windows 子系统 Linux(Ubuntu 18.04)，并在其中安装了 Maven.另外，我之前在Win10中安装了一个maven.现在，当我在 WSL 中使用 mvn compile 时，它告诉我 maven 编译失败.我使用which mvn发现它引用了Win10中安装的Maven.

I use Windows Subsystem Linux(Ubuntu 18.04) in my Win10, and I install a Maven in it. Besides, I install a maven in Win10 before. Now when I used mvn compile in WSL, it told me that maven compile fail. I use which mvn and find that it references to the Maven installed in Win10.

另外，我运行env，发现WSL的Path中添加了Win10的Path.用WSL的时候不想用Win10的Path里面的东西，怎么办?

Besides, I run env and find that Win10's Path is added to the WSL's Path. I don't want to use any thing in Win10's Path when I use WSL, how should I do?

推荐答案

• 对于低于 17713 的 Windows 版本:WSL 使用 WSL_DISTRIBUTION_FLAGS 枚举 来配置其行为以及 Windows 和 Linux 端之间的互操作性.这是来自 wslapi.h 头文件的代码片段.

  • For Windows build LOWER than 17713: WSL uses WSL_DISTRIBUTION_FLAGS Enumeration to configure its behavior and interoperability between Windows and Linux side. Here is the code snippet from wslapi.h header file.

      /* Flags specifying WSL behavior */
      typedef enum
      {
          WSL_DISTRIBUTION_FLAGS_NONE                  = 0x0,
          WSL_DISTRIBUTION_FLAGS_ENABLE_INTEROP        = 0x1,
          WSL_DISTRIBUTION_FLAGS_APPEND_NT_PATH        = 0x2,
          WSL_DISTRIBUTION_FLAGS_ENABLE_DRIVE_MOUNTING = 0x4
      } WSL_DISTRIBUTION_FLAGS;
    
      #define WSL_DISTRIBUTION_FLAGS_VALID (WSL_DISTRIBUTION_FLAGS_ENABLE_INTEROP | WSL_DISTRIBUTION_FLAGS_APPEND_NT_PATH | WSL_DISTRIBUTION_FLAGS_ENABLE_DRIVE_MOUNTING)
      #define WSL_DISTRIBUTION_FLAGS_DEFAULT (WSL_DISTRIBUTION_FLAGS_ENABLE_INTEROP | WSL_DISTRIBUTION_FLAGS_APPEND_NT_PATH | WSL_DISTRIBUTION_FLAGS_ENABLE_DRIVE_MOUNTING)
    

    首次启动时，WSL 使用默认标志 ​​= 0x7(即 0+1+2+4).如果该标志 = 0x5(即 0+1+4)Windows NT 路径将不会附加到 $PATH 环境变量中.那么，如何找到标志注册表值呢?在注册表编辑器中打开 HKCUSoftwareMicrosoftWindowsCurrentVersionLxss 注册表路径.regedit.exe.使用 UID 值打开每个子项，并将 DistributionName 与您安装的分发名称匹配.然后将 Flags DWORD 注册表值编辑/添加到 0x5.

    At first launch, WSL uses the default flag = 0x7 (i.e. 0+1+2+4). If that flag = 0x5 (i.e. 0+1+4) Windows NT path will not appended in $PATH environment variable. So, how to find that flags registry value? Open HKCUSoftwareMicrosoftWindowsCurrentVersionLxss registry path in Registry Editor aka. regedit.exe. Open each subkey with UID values and match DistributionName with your installed distribution name. Then edit/add the Flags DWORD registry value to 0x5.

    对于 Windows 版本 高于 17713:在新版本中 WSL 使用 wsl.conf 文件 来配置它的行为和 Windows 和 Linux 端之间的互操作性.该 wsl.conf 文件遵循 INI 文件格式.运行 wsl.exe 或 bash.exe.创建文件 /etc/wsl.conf.然后添加以下 interop 部分以及任何文本Linux 中的编辑器.

    For Windows build HIGHER than 17713: In new build WSL uses wsl.conf file to configure its behavior and interoperability between Windows and Linux side. That wsl.conf file follows INI file format. Run wsl.exe or bash.exe. Create a file /etc/wsl.conf. Then add the following interop section with any text editor in Linux.

      [interop]
      enabled=false # enable launch of Windows binaries; default is true
      appendWindowsPath=false # append Windows path to $PATH variable; default is true
    

    保存该文件并从 wsl.exe 退出.现在，无论何时执行 WSL，Windows 路径都不会附加到 Linux $PATH 环境变量中.

    Save that file and exit from wsl.exe. Now whenever WSL is executed Windows paths will not appended to Linux $PATH environment variable.

    如 AndrewBourgeois 所述，您可能需要使用 wsl --shutdown 或 wsl -t 关闭 wsl 的当前实例以使更改生效.

    As mentioned by AndrewBourgeois, you may need to shutdown the current instance of wsl with wsl --shutdown or wsl -t <Distribution> for changes to take effect.

    这篇关于如何从 WSL 中删除 Win10 的 PATH的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！