反转haskell中的列表 [英] Reverse a list in haskell

问题描述

我正在尝试反转列表.

以下是我的代码:

reverseList :: [Int] -> [Int]
reverseList [] = []
reverseList (x:xs) =  x:reverseList xs

最终发生的事情是我最终以相同的顺序取回列表.我什至有一个如何反转列表的解决方案，但我试图了解我在这里做错了什么?我对 haskell 很陌生，所以我认为我应该专注于理解更多，然后才能轻松解决更多问题.我知道这个问题有很多解决方案，但我需要更多帮助来理解我在这段代码中做错了什么.

What ends up happening is I end up getting the list back in same order. I even have a solution for how to reverse the list but I am trying to understand what I did wrong here ? I am very new to haskell so think I should focus on understanding more then I can solve more problems with ease. I know there are many solutions out there for this problem but I need more help in the understanding esp what I did wrong here in this code.

推荐答案

您将列表分成头部和尾部，然后以相同的顺序重新组合列表.以列表[1, 2, 3]为例:

You are separating the list into head and tail, but then re-assemble the list in the same order. Take the list [1, 2, 3] for example:

在第一次调用中，x 将是 1，而 xs 将是 [2, 3].然后创建一个新列表，由前面的 x (so 1) 和 reverseList [2, 3] 组成.

In the first call, x will be 1, and xs will be [2, 3]. Then you create a new list, consisting of x (so 1) at the front, followed by reverseList [2, 3].

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