(作业)MVC分页帮助 [英] (Homework) MVC Pagination Help
问题描述
我试图放在一起使用ASP.NET MVC一个非常简单的应用程序,显示新闻报道和进行分页他们。我是那种中途有,但需要一些帮助整理出分页和得到它与搜索查询工作。
I'm attempting to put together a very simple application using ASP.NET MVC that shows news articles and paginates them. I'm sort of half-way there but need some help sorting out the pagination and getting it to work with the search query.
下面是我的HomeController:
Here is my HomeController:
public ActionResult Index(String query, int? page)
{
// limit the number of articles per page
const int pageSize = 4;
// build the query
var ArticleQuery = from a in _db.ArticleSet select a;
// check if their is a query
if (!string.IsNullOrEmpty(query))
{
ArticleQuery = ArticleQuery.Where(a => a.headline.Contains(query));
}
// orders the articles
var OrderedArticles = ArticleQuery.OrderByDescending(a => a.posted);
// takes the ordered articles and paginates them
//var paginatedArticles = new PaginatedList(OrderedArticles.Skip((page ?? 0) * pageSize).Take(pageSize), page ?? 0, pageSize);
var paginatedArticles = new PaginatedList<Article>(OrderedArticles, page ?? 0, pageSize);
// return the paginated articles to the view
return View(paginatedArticles);
}
的想法是,控制器显示4个项目每页会按日期排序。这里是查看我对指数的方法:
The idea is that the Controller shows 4 items per page will order them by date. Here is the View I have for the Index method:
<ul id="pagination">
<% if (Model.PreviousPage) { %>
<li><%= Html.ActionLink("<< First Page", "Index")%></li>
<li><%= Html.ActionLink("<< Previous Page", "Index", new { page=(Model.PageIndex-1) }) %></li>
<% } %>
<% if (Model.NextPage) { %>
<li><%= Html.ActionLink("Next Page >>", "Index", new { page = (Model.PageIndex + 1) })%></li>
<li><%= Html.ActionLink("Last Page >>", "Index", new { page = (Model.TotalPages - 1) })%></li>
<% } %>
</ul>
我们的想法是,如果条件为真,这两个分页链接才会显示。
The idea is that these two pagination links will only show if the conditions are true.
最后这里是寻呼机的PaginatedList类:
Finally here is the PaginatedList class for the pager:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using System.Web.Routing;
namespace NewsApp.Models
{
public class PaginatedList<T> : List<T>
{
public int PageIndex { get; private set; }
public int PageSize { get; private set; }
public int TotalCount { get; private set; }
public int TotalPages { get; private set; }
public PaginatedList(IQueryable<T> source, int pageIndex, int pageSize)
{
PageIndex = pageIndex;
PageSize = pageSize;
TotalCount = source.Count();
TotalPages = (int)Math.Ceiling(TotalCount / (double)PageSize);
this.AddRange(source.Skip(PageIndex * PageSize).Take(PageSize));
}
public bool HasPreviousPage
{
get
{
return (PageIndex > 0);
}
}
public bool HasNextPage
{
get
{
return (PageIndex + 1 < TotalPages);
}
}
}
注意:我不想用任何第三方组件,如MVCContrib等,因为这是一个大学分配,以便将击败目的
分页现在工作正常,但是当我做了搜索,并有例如?/查询=测试中,我希望能够到页面的结果,此刻,他们迷路:/
The pagination works fine now but when I do a search and have e.g. /?query=test I want to be able to page the results, at the moment they get lost :/
感谢。
推荐答案
您没有提到你在做什么实际的错误是,但我想我看到什么是错的:
You didn't cite what you're actual error is, but I think I see what's wrong:
这两条线将返回包含您的一个IEnumerable的结果。
These two lines will return your an IEnumerable containing your results.
var paginatedArticles = OrderedArticles.Skip((page ?? 0) * pageSize).Take(pageSize).ToList();
return View(paginatedArticles);
然而,根据你的看法和您发布的辅助类,你认为期待 PaginatedList
对象作为它的模型。
如果是这样的话,我会做以下(更新)
If that's the case, I'd do the following (updated):
var paginatedArticles = new PaginatedList( OrderedArticles, page ?? 0, pageSize );
return View(paginatedArticles);
和那么你认为应该有适当的模型被返回给它。
And then your view should have the proper model being returned to it.
这是说:我不知道你为什么不使用存储库层,但除非你的应用程序只有一个页面几乎总是有一个到位是个好主意。
That said: I don't know why you aren't using a repository layer, but unless your app is only a single page it is almost always a good idea to have one in place.
更新 --here就是我认为的完全控制逻辑应该是:
Update --here's what I think the full controller logic should be:
public ActionResult Index(String query, int? page)
{
const int pageSize = 4;
var ArticleQuery = from m in _db.ArticleSet select m;
// Searching
if (!string.IsNullOrEmpty(query))
{
ArticleQuery = ArticleQuery.Where(m => m.headline.Contains(query));
}
var OrderedArticles = ArticleQuery.OrderByDescending(m => m.posted);
var paginatedArticles = new PaginatedList( OrderedArticles, page ?? 0, pageSize );
// this will now be of type paginatedList. this class handles all of the paging for you, so no need to do that ahead of time
return View(paginatedArticles);
}
在这种情况下,PaginatedList不是一个帮手--its全上需要创建并传递给你的模型类。在这个词的严格定义助手就是不同多少事,可能就不会在你的情况在这里工作。
In this case, PaginatedList is NOT a helper --its a full on class that needs to be created and passed to your model. A helper in the strict definition of the word is done much differently and probably wouldn't work in your case here.
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