更改 url (Django) 中的一个查询参数 [英] Altering one query parameter in a url (Django)

问题描述

我有一个采用各种参数的搜索页面.我想通过更改查询中的一个参数来创建一个新 URL.有没有一种简单的方法可以做到这一点 - 比如:

# 示例请求 urlhttp://example.com/search?q=foo&option=bar&option2=baz&change=before# 理想的模板代码{% url_with change 'after' %}# 结果网址http://example.com/search?q=foo&option=bar&option2=baz&change=after

所以这将获取请求 url，更改一个查询参数，然后返回新的 url.类似于在 Perl 的 Catalyst 中使用 $c->uri_with({change => 'after'}) 可以实现的功能.

或者有更好的方法吗?

[更新:删除了对分页的引用]

解决方案

所以，围绕这个写一个模板标签:

from urlparse import urlparse, urlunparse从 django.http 导入 QueryDictdef replace_query_param(url, attr, val):(scheme, netloc, path, params, query, fragment) = urlparse(url)query_dict = QueryDict(query).copy()query_dict[attr] = val查询 = query_dict.urlencode()返回 urlunparse((scheme, netloc, path, params, query, fragment))

要获得更全面的解决方案，请使用 Zachary Voase 的 URLObject 2，做得非常好.>

注意:urlparse 模块在 Python 3 中重命名为 urllib.parse.

I have a search page that takes a variety of parameters. I want to create a new URL by just altering one parameter in the query. Is there an easy way to do this - something like:

# example request url
http://example.com/search?q=foo&option=bar&option2=baz&change=before

# ideal template code
{% url_with change 'after' %}

# resulting url
http://example.com/search?q=foo&option=bar&option2=baz&change=after

So this would take the request url, alter one query parameter and then return the new url. Similar to what can be achieved in Perl's Catalyst using $c->uri_with({change => 'after'}).

Or is there a better way?

[UPDATED: removed references to pagination]

解决方案

So, write a template tag around this:

from urlparse import urlparse, urlunparse
from django.http import QueryDict

def replace_query_param(url, attr, val):
    (scheme, netloc, path, params, query, fragment) = urlparse(url)
    query_dict = QueryDict(query).copy()
    query_dict[attr] = val
    query = query_dict.urlencode()
    return urlunparse((scheme, netloc, path, params, query, fragment))

For a more comprehensive solution, use Zachary Voase's URLObject 2, which is very nicely done.

Note: The urlparse module is renamed to urllib.parse in Python 3.

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