Django 传递对象以包含 [英] Django pass object to include

问题描述

我无法在 Django 中执行以下操作:

I cannot do the following in Django:

{% include "admin/includes/pager.html" with title_pager="{{myobject.title}}" %}

或

{% include "admin/includes/pager.html" with title_pager="{{myobject}}" %}

解决方法是什么?

推荐答案

你不需要在模板标签中用 {{ }} 括号括起参数.

You do not need to surround arguments in {{ }} brackets in template tags.

如果它是一个变量，而不是一个字符串，那么不要使用 "" 引号.

If it's a variable, not a string, then do not use "" quotes.

以下应该有效:

{% include "admin/includes/pager.html" with title_pager=myobject.title %}

{% include "admin/includes/pager.html" with title_pager=myobject %}

请参阅 Django 文档中的 include 标签更多信息.

See the Django docs for the include tag for more information.

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