Django - 得到错误“Reverse for 'detail'，没有找到任何参数.尝试了 1 个模式:"当使用 {% url "music:fav";%} [英] Django - getting Error "Reverse for 'detail' with no arguments not found. 1 pattern(s) tried:" when using {% url "music:fav" %}

问题描述

我从过去 4 天开始学习 django 框架.今天我试图通过使用

I am learning django framework from last 4 days. Today I was trying to retrieve a URL in HTML template by using

{% url "music:fav" %}

{% url "music:fav" %}

我将 music/urls.py 中的命名空间设置为

where I set the namespace in music/urls.py as

app_name="音乐"

app_name= "music"

而且我还有一个名为 fav() 的函数.代码如下:

and also I have a function named fav(). Here is the codes:

音乐/urls.py

from django.urls import path
from . import views
app_name = 'music'

urlpatterns = [
path("", views.index, name="index"),
path("<album_id>/", views.detail, name="detail"),
path("<album_id>/fav/", views.fav, name="fav"),
]

音乐/views.py

music/views.py

def fav(request):
    song = Song.objects.get(id=1)
    song.is_favorite = True
    return render(request, "detail.html")

我使用的detail.html

in detail.html I used

{% url 'music:fav' %}

但我不知道为什么会显示此错误:

But I dont know why this is showing this error:

NoReverseMatch at/music/1/Reverse for 'detail' with no arguments not成立.尝试了 1 个模式:['music/(?P[^/]+)/$']

NoReverseMatch at /music/1/ Reverse for 'detail' with no arguments not found. 1 pattern(s) tried: ['music/(?P[^/]+)/$']

推荐答案

path("<album_id>/fav/", views.fav, name="fav"),

此 URL 需要 album_id.像这样:

This URL needs the album_id. Something like this:

{% url 'music:fav' 1 %}
{% url 'music:fav' album.id %}

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