在clojure中如何映射重叠对? [英] In clojure how to map over overlapping pairs?

问题描述

假设我有序列:

[1 2 3 4 5]

我想成对地映射它们:

[(1, 2), (2, 3), (3, 4), (4, 5)]

我试过了:

(map f (partition 2 [1 2 3 4]))

但这会导致成对序列:

[(1, 2), (3, 4)]

我怎样才能获得所需的功能?

How can I get the desired functionality?

推荐答案

默认情况下 partiton 返回非重叠分区，但您可以提供 step 参数来提供创建分区的偏移量:

By default partiton returns non-overlapping partitions, but you can supply a step argument to provide the offset at which partitions are created:

clojure.core/partition
([n coll] [n step coll] [n step pad coll])
  Returns a lazy sequence of lists of n items each, at offsets step
  apart. If step is not supplied, defaults to n, i.e. the partitions
  do not overlap. If a pad collection is supplied, use its elements as
  necessary to complete last partition upto n items. In case there are
  not enough padding elements, return a partition with less than n items.

这会做你想做的:

(partition 2 1 [1 2 3 4 5 6 7 8]))
; #=> ((1 2) (2 3) (3 4) (4 5) (5 6) (6 7) (7 8))

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